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Mashutka [201]
3 years ago
10

Find the gradient, picture below

Mathematics
2 answers:
hoa [83]3 years ago
3 0

Answer:

\frac{dy}{dx}  =  \frac{13}{8}

Step-by-step explanation:

y = 2x + 6 {x}^{ -  \frac{1}{2} }  \\  \frac{dy}{dx} = 2 + 6( -  \frac{1}{2}) {x}^{ -  \frac{1}{2} - 1 }   \\  \frac{dy}{dx}  = 2 - 3 {x}^{ -  \frac{3}{2} }  \\ \frac{dy}{dx}  = 2 -  \frac{3}{ \sqrt{ {x}^{3} } }

When x = 4,

\frac{dy}{dx}  = 2 -  \frac{3}{ \sqrt{ {4}^{3} } }  \\  =  \frac{13}{8}

alexira [117]3 years ago
3 0

Answer:

Hello,

Answer 13/8

Step-by-step explanation:

y=2x+\dfrac{3}{\sqrt{x} } \\\\y'=2+6*\dfrac{-1}{2} x^{\frac{-3}{2} }\\\\y'=3-\frac{3}{\sqrt{x^3}} \\\\\\For x=4, \\\\y'(4)=2-\dfrac{3}{8} =\dfrac{13}{8}

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