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beks73 [17]
3 years ago
5

8y-2d=0 5y+4d=26 1/4

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

y = 1

d = 4

Step-by-step explanation:

8y - 2d = 0 ---------------(I)

5y + 4d = 26 1/4

5y + 4d =  105/4  ------------------(II)

(I)*2      16y  - 4d = 0

(II)          <u>5y + 4d = 105/4</u>      {add (I) &(II)}

             21y        = 105/4

y = \frac{105}{5*21}\\\\y=\frac{105}{105}\\\\y = 1

Substitute y =1 in equation (I)

8*1 - 2d = 0

8 - 2d = 0

   -2d = -8

      d = -8/-2

d = 4

Harman [31]3 years ago
5 0

Answer:

  (y, d) = (1.25, 5)

Step-by-step explanation:

We can add twice the first equation to the second.

  2(8y -2d) +(5y +4d) = 2(0) +26 1/4

  21y = 26 1/4

  y = (105/4)/21 = 105/84 = 5/4

  8(5/4) -2d = 0

  5 = d . . . . . . . . . . add 2d, divide by 2

The solution to this system of equations is ...

  y = 5/4, d = 5

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cooper's jump rope is for 4 2/5. luke's jump rope is 4 3/4 ft long. whose jump rope is longer? how much longer? show your work
Hoochie [10]

Answer:

Juke's jump; by 0.35 feet

Step-by-step explanation:

Given that,

Cooper's jump rope is for 4\dfrac{2}{5} feet.

Juke's jump rope is 4\dfrac{3}{4} feet.

Cooper's jump is :

4\dfrac{2}{5}=\dfrac{22}{5}\ \text{feet}\\\\=4.4\ \text{feet}

Juke's jump is

4\dfrac{3}{4}=\dfrac{19}{4}\\\\=4.75\ \text{feet}

So, it is clear that Juke's jump is longer than Cooper's jump.

Juke's jump - Cooper's jump = 4.75 - 4.4

= 0.35 feet

or

So, Juke's jump is 375 feet longer.

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3 years ago
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alina1380 [7]
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4 years ago
A pharmaceutical company claimed that experiments showed that its drug could effectively reduce the growth of cancer cells by 35
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3 years ago
Read 2 more answers
In the coordinate plane, the point A, 4− 2 is translated to the point A′, 1− 5. Under the same translation, the points B, 7− 4 a
Inga [223]

Answer:

The coordinates of B' and C' are B'(x,y) = (4, -7) and C'(x,y) = (-1, -8), respectively.

Step-by-step explanation:

From the Linear Algebra, we define the translation of a given point as:

O'(x,y) = O(x,y) + T(x,y) (1)

Where:

O(x,y) - Original point, dimensionless.

T(x,y) - Translation vector, dimensionless.

O'(x,y) - Translated point, dimensionless.

If we know that A'(x,y) = (1, -5) and A(x,y) = (4,-2), then the translation vector is:

T(x,y) = A'(x,y)-A(x,y) (2)

T(x,y) = (1,-5)-(4,-2)

T(x,y) = (-3,-3)

If we know that B(x,y) = (7,-4), C(x,y) = (2,-5) and T(x,y) = (-3,-3), then the translated points are, respectively:

B'(x,y) = B(x,y)+T(x,y) (3)

B'(x,y) = (7,-4) +(-3,-3)

B'(x,y) = (4, -7)

C'(x,y) = C(x,y) +T(x,y)

C'(x,y) = (2,-5) + (-3,-3)

C'(x,y) = (-1, -8)

The coordinates of B' and C' are B'(x,y) = (4, -7) and C'(x,y) = (-1, -8), respectively.

5 0
3 years ago
Is the point (5,8) a solution to the system of equations shown below? Justify your response
AlladinOne [14]

Step-by-step explanation:

For the point (5,8) to be a solution to the equations, when you insert x=5 and y=8 , they have to equal to the given values

substituting (5,8) into 4x+y

4(5)+8

=20+8

=28

substituting(5,8) into x-y=3

5-8

= -3

5 0
3 years ago
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