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beks73 [17]
2 years ago
5

8y-2d=0 5y+4d=26 1/4

Mathematics
2 answers:
Anit [1.1K]2 years ago
7 0

Answer:

y = 1

d = 4

Step-by-step explanation:

8y - 2d = 0 ---------------(I)

5y + 4d = 26 1/4

5y + 4d =  105/4  ------------------(II)

(I)*2      16y  - 4d = 0

(II)          <u>5y + 4d = 105/4</u>      {add (I) &(II)}

             21y        = 105/4

y = \frac{105}{5*21}\\\\y=\frac{105}{105}\\\\y = 1

Substitute y =1 in equation (I)

8*1 - 2d = 0

8 - 2d = 0

   -2d = -8

      d = -8/-2

d = 4

Harman [31]2 years ago
5 0

Answer:

  (y, d) = (1.25, 5)

Step-by-step explanation:

We can add twice the first equation to the second.

  2(8y -2d) +(5y +4d) = 2(0) +26 1/4

  21y = 26 1/4

  y = (105/4)/21 = 105/84 = 5/4

  8(5/4) -2d = 0

  5 = d . . . . . . . . . . add 2d, divide by 2

The solution to this system of equations is ...

  y = 5/4, d = 5

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Select the coordinate point that is a solution of equations. 2x+y=7; 3x-4y=5
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The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de
antoniya [11.8K]

Answer:

a) P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b) P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c) P(A') = 1-P(A) =1-0.4=0.6

d) P(A \cup B) =0.4 +0.8-0.2 =1.0

e)  The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

Step-by-step explanation:

We have the following space provided:

S= [a,b,c,d,e]

With the following probabilities:

P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

P(A) = 0.1+0.1+0.2 = 0.4

P(B) =0.2+0.4+0.2=0.8

Determine:

a. P(A)

P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4

b. P(B)

P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8

c. P(A’)

From definition of complement we have this:

P(A') = 1-P(A) =1-0.4=0.6

d. P(AUB)

Using the total law of probability we got:

P(A \cup B) =P(A) +P(B)-P(A \cap B)

For this case P(A \cap B) = P(c) =0.2, so if we replace we got:

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e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

P(A \cap B) = P(c) =0.2

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