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Dvinal [7]
3 years ago
15

Stella and brain each heat up a small pizza.stella cuts her pizza into 4 equal slices. Brain cuts his pizza into 8 equal parts,S

tella eats two pieces of her pizza Brian eats four pieces of his pizza do they eat the same amount of pizza? PLEASE ANSWER!!!!
​
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

They are the same amount of pizza.

Step-by-step explanation:

    Stella cut her pizza into 4 pieces. If she eats 2 pieces, then she has eaten half of her pizza. Likewise, Brian cut his pizza into 8 pieces. If he eats 4 pieces, then he has eaten half of his pizza. Therefore, they have both eaten the same amount of pizza.

Model:

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The following set of linear equations 2x+2y=18 x+3y=17
NemiM [27]

Answer:

x = 5

y = 4

Step-by-step explanation:

1. 2x + 2y = 18

2. x + 3y = 17

Multiply the first equation by 1 and the second equation by 2 to eliminate x

We have

2x + 2y = 18

2x + 6y = 34

Subtract equation 2 from equation 1

-4y = -16

Divide both sides by -4 to isolate y

-4y/-4 = -16/-4

y = 4

Now substitute 4 for y in either equation to get x. Using equation 2 we have

x + 3y = 17

x + 3 x 4 = 17

x + 12 = 17

Subtract 12 from both sides

x + 12 - 12 = 17 - 12

x = 5

x = 5 and

y = 4

8 0
3 years ago
1) A traditional die is a cube with each of its six sides representing the numbers from 1 to 6. Mr. Dicey customized a die by re
liraira [26]

Answer:

1) \frac{2}{5}

2) 49.225

3) \frac{7}{2}

Step-by-step explanation:

1) To find the expected value of the dice we can use the following equation:

E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})

So in our problem the values x will be: 1/1, 1/2, 1/3, 1/4, 1/5 and 1/6 and the probavility for all values is 1/6 so the expected values will be:E(x)=(\frac{1}{1} *\frac{1}{6}) +(\frac{1}{2} *\frac{1}{6}) +(\frac{1}{3} *\frac{1}{6})+(\frac{1}{4} *\frac{1}{6})+(\frac{1}{5} *\frac{1}{6})+(\frac{1}{6} *\frac{1}{6})

E(x)=0.167+0.083+0.056+0.042+0.033+0.028=0.409\approx \frac{2}{5}

2) To find the variance of the expected values we can use the equation:

Var(x)=\frac{\sum_{i=1}^{n}(x_{i}-\overline{x})^{2} }{n}

So for our problem will be:

Var(x)=\frac{(3-10.5)^2+(4-10.5)^2+(17-10.5)^2+(18-10.5)^2}{4}

Var(x)=\frac{56.25+42.25+42.25+56.25}{4}Var(x)=\frac{196.9}{4}=49.225

3) To find the expected value of the dice we can use the following equation:

E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})

So in our problem the values x will be: 1, 2, 3, 4, 5 and 6 and the probavility for all values is 1/6 so the expected values will be:E(x)=(1*\frac{1}{6}) +(2 *\frac{1}{6}) +(3 *\frac{1}{6})+(4 *\frac{1}{6})+(5 *\frac{1}{6})+(6 *\frac{1}{6})

E(x)=0.17+0.33+0.5+0.67+0.83+1=3.5\approx \frac{7}{2}

7 0
3 years ago
Really need help, I just want to know the steps to solve these type of problems!
Nonamiya [84]

Answer:

12/6 = 2

x=2

Step-by-step explanation:

i hope this help

let me kow if it did

3 0
3 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
The difference between 3 times a number and 21
Over [174]

Answer:

3 times 7 = 21

Step-by-step explanation:

5 0
3 years ago
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