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-BARSIC- [3]
3 years ago
13

Let f(x) = 8x3 + 16x2 − 15 and g(x) = 2x + 1. Find f of x over g of x. WILL GIVE BRAINLIEST!

Mathematics
2 answers:
podryga [215]3 years ago
4 0

Answer:

  • 4x² + 6x - 3 remainder -12

Step-by-step explanation:

<u>Given:</u>

  • (x) = 8x³ + 16x² − 15
  • g(x) = 2x + 1

<u>To find:</u>

  • f(x) / g(x)

<u>Use long division:</u>

  • f(x) / g(x) =
  • (8x³ + 16x² − 15) / (2x + 1)

2x + 1  | (8x³ + 16x² − 15

           <u>| 8x³ + 4x²</u>

                     12x² + 0x - 15

                     <u>12x² + 6x</u>

                               -6x - 15

                               <u>-6x - 3</u>

                                      -12

4x² + 6x - 3 remainder -12

elena-14-01-66 [18.8K]3 years ago
4 0
  • f(x)=8x^3+16x^2-15
  • g(x)=2x+1

\sf \dfrac{f(x)}{g(x)}

\\ \rm\longmapsto \dfrac{8x^2+16x^2-15}{2x+1}

Refer to attachment now

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If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find ƒ(-1) + 5g(-3).<br><br> -40<br> -38<br> 7
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f(x) = x^2 + 1 \\ &#10;g(x) = 3x + 1

You can do this in parts.
f(-1) = (-1)^2 + 1 = 1 + 1 = 2
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Or you can do this as one big chunk.
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