the 1 is the h and the -2 is the k
f(x) = a(x - h)^2 + k
f(x) = a(x-1)^2 -2
to find a substitute x=3, y=6 in
6= a(3-1)^2 -2
6 =a *2^2 -2
add 2 to each side
8 = 4a
a =2
f(x) = 2(x-1)^2 -2 this is the vertex form
distribute to get the standard from
f(x) = 2(x^2-2x+1) -2
2x^2 -4x+2-2
f(x) =2x^2-4x is the standard form
Choice A
That second "line" isn't a line. It's nothing. Therefore, the first line cannot be parallel or perpendicular to it because it doesn't exist.
20m^2 is area.
height is 4m.
20*2 = 40
40/4 = 10
the answer is 10m