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MariettaO [177]

3 years ago

13

A trapezoid has a height of 6 ft and a total area of 30 ft^. What are the possible lengths of the bases. Explain your reasoning.

1 answer:

gtnhenbr [62]3 years ago

3 0

The area of a trapezoid = (a + b)/2 x h
Where a and b are the lengths of the parallel sides and h is the perpendicular distance between them.
When (a + b)/2 x 6 = 30
then (a + b)/2 = 5
a + b = 10

Possible values for (a,b) are (4,6) (3,7) (2,8) (1,9) assuming a < b but (7,3) is also valid.
Any positive real value is possible so (4.8, 5.2) and (0.3, 9.7) are valid

In general {a,b both real: 0

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find the particular solution to the exact differentiable equation dy/dx=(2e^x)-cosx passing through the point (0,3)

lozanna [386]

Answer:

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Step-by-step explanation:

dy/dx = 2eˣ - cos x

(0, 3)

Integrate dy/dx to find the original function.

y = 2eˣ - sin x + C

Solve for C by substituting the point given.

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2 years ago

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If the trapezoid on the grid below is translated by using the rule (x,y)-> (x-4,y-3) what will be the coordinates of B’?

vesna_86 [32]

Answer:

B'(3, 5)

Step-by-step explanation:

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If h = 4 and k = 3,

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