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Xelga [282]
3 years ago
6

The perimeter of a rectangular garden is 24. If the length is half the width, what is the width?

Mathematics
2 answers:
Anna11 [10]3 years ago
4 0

Let length be x

  • Width be 2x

ATQ

\\ \sf\longmapsto 2(L+B)=24

\\ \sf\longmapsto 2(x+2x)=2=

\\ \sf\longmapsto 2(3x)=24

\\ \sf\longmapsto 6x=24

\\ \sf\longmapsto x=\dfrac{24}{6}

\\ \sf\longmapsto x=4

Ber [7]3 years ago
3 0

Step-by-step explanation:

let the length be X and breadth be 2x

p=2(l+b)

24=2(X+2x)

24=2x+4x

24=6x

24÷6=x

4=X

so,we know that

X=4 and 2x=2 X 4= 8

therefore the value of breadth or width is 8

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SVETLANKA909090 [29]

Answer:

X = 9, -1

Step-by-step explanation:

1, Factor it

(x-9) (x+1) = 0

2. Both of a factor will = 0

x-9 = 0

x+1=0

3. Solve

x=9

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7 0
3 years ago
What is the solution set for the molar concentration of
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Answer: B

Step-by-step explanation:

I got it right on Edge

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Two numbers are in the ratio 7:9 if the sum of the number is 112 then the lrger number is?
nordsb [41]

Answer:

63

Step-by-step explanation:

the numbers are in ratio 7 : 9 = 7x : 9x ( x is a multiplier )

given the sum of the numbers = 112 , then

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16x = 112 ( divide both sides by 16 )

x = 7 , then

9x = 9 × 7 = 63 ← value of larger number

7 0
1 year ago
Divid 15 into two parts such that the sum of their reciprocal is 3/10
Klio2033 [76]
From the information obtained from the question, two equations can be created:
 
Let x and z be the two numbers (parts)

\frac{1}{z}   +   \frac{1}{x}  =   \frac{3}{10} .  .  .  . (1)

z  +   x  =  15  .  .  .  . (2)

By transposing (2), make 'z' the subject of the equation
z = 15 - x  .  .  .  . (3)

By substituting (3) into equation (1) to find a value for x
\frac{1}{(15 - x)} + \frac{1}{x} = \frac{3}{10}

\frac{15}{( 15 - x ) ( x )}  =   \frac{3}{10}

3 ( - x^{2}  + 15 x )  =  150

3 x^{2}  - 45x + 150 = 0

⇒  ( x - 5 )  ( x - 10 )  = 0

∴ either ( x - 5) = 0        OR    ( x - 10 ) = 0

Thus x = 5 or x = 10

By substituting the values of x into (2) to find z

     z + (5) = 15       OR      z + (10) = 15

    ⇒      z = 10      OR                 z = 5

So, the two numbers or two parts into which fifteen is divided to yield the desired results are 5 and 10.





5 0
3 years ago
I did the first one but can you help me with the second one plz??
yanalaym [24]

the only like-terms are on the right-hand-side, since the left-hand-side has only 1 term anyway.

\bf \cfrac{5}{2}s=\cfrac{3}{2}s+s\implies \cfrac{5}{2}s=\cfrac{3}{2}s+\cfrac{s}{1}\implies \cfrac{5}{2}s=\stackrel{\textit{using the LCD of 2}}{\cfrac{(1)3s+(2)s}{2}} \\\\\\ \cfrac{5}{2}s=\cfrac{3s+2s}{2}\implies \cfrac{5}{2}s = \cfrac{5}{2}s

5 0
3 years ago
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