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3 years ago

How do I solve this pls help?

Mathematics

2 answers:

Alexxandr [17]3 years ago

4 0

Answer:

f(0) = 4, from the graph

h(11) = 15, from the table

g(-9) = -2(-9)² - 4(-9) + 1 = -125, as per equation

f(2) = 1, from the graph

h(-2) = 2, from the table

g(0.25) = -2(0.25)² - 4(0.25) + 1 = - 0.125, as per equation

Yakvenalex [24]3 years ago

4 0

f(0) = 4

h(11) = 15

g(-9) = -2(-9)² - 4(-9) + 1 = -125

f(2) = 1

h(-2) = 2

g(0.25) = -2(0.25)² - 4(0.25) + 1 = - 0.125

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2x−9y=14 x=−6y+7 x=____, y=___, equals

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Y=0,x=7. Please see the attachment for answers, details and explanation.

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4 years ago

9y + 3 = 21<br> Solve for the variable

wel

Answer:

y = 2

The variable is equal to 2

Step-by-step explanation:

9y + 3 = 21

-3 -3

9y = 18

Divide both sides by 9

y = 2

5 0

3 years ago

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the first term of an arithmetic sequence is 4 and the tenth term is 10. how can you find the sixth term of the sequence.

wel

Step-by-step explanation:

Let 1st term be (a) and common difference between sequence be (d).then according to question:

a=4

a+9d=10

i.e 4+9d=10

or, 9d=10 - 4

or, d= 6÷9

Hence,d=2/3

Now,

As,sixth term =a+5d

=4+5(2/3)

=4+(10/3)

=(12+10)÷3

=22÷3

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3 years ago

The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking

vladimir2022 [97]

Answer:

A sample of 767 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

14 defectives out of 160, so $\pi = \frac{14}{160} = 0.0875$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How many units would have to be sampled to be 95% confident that you can estimate the fraction of defective parts within 2% of the percentage?

We would need a sample of n.

n is fround when $M = 0.02$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.0875*0.9125}{n}}$

$0.02\sqrt{n} = 1.96\sqrt{0.0875*0.9125}$

$\sqrt{n} = \frac{1.96\sqrt{0.0875*0.9125}}{0.02}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.0875*0.9125}}{0.02})^2$

$n = 766.8$

Rounding up

A sample of 767 is needed.

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3 years ago

Numbers with the same absolute value are

Vikentia [17]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ The correct answer is D. equally distant

The absolute value is a number's distance from 0 and that number will always be equally distant.

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~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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3 years ago

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