Percent error = (estimate - real)/(real) * 100
percent error = (78.25 - 75.50)/(75.50) * 100
percent error = 3.6%
Answer:
the no of liters required is 50.55 liters
Step-by-step explanation:
Given that
The car gas efficiency is 23.0 mi/gal
distance is 495 km
1 gal = 3.78 L
1 km = 0.6214 mi
We need to find out the no of liters of gas that would needed to complete a trip
So,
= (495 × 3.78 × 0.6214) ÷ (23)
= 50.55 Liters
hence, the no of liters required is 50.55 liters
Just copy this down. you welcome
