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natali 33 [55]
3 years ago
9

A parallelogram has a base of 7 meters and a height of 10 meters. What is the area of the parallelogram in square meters?​

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Step-by-step explanation:

Area of a parallelogram = H * B

Where ;H = height and B = 7

From the question our height = 10m and base = 7m

<h3>placing in formula</h3>

H * B

= 10m * 7m

=70m²

Therefore the area of the parallelogram is 70m²

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The area of tapazuim is 400 cm 2 the distance between the parallel sides is 16 cm.if one of the parralel sides is 20 cm,find the
german

the other parallel side is 30 cm

Step-by-step explanation:

here's the solution :-

let the other parallel side be x

now,

=》Area of trapezium =

\frac{1}{2}  \times sum \: of \: parallel \: sides \times height =》[tex] \frac{1}{2}  \times (x + 20) \times 16 = 400

=》( x + 20 ) × 8 = 400

=》x + 20 = 400 ÷ 8

=》x = 50 - 20

=》x = 30

so length of other parallel side = x = 30 cm

4 0
3 years ago
If f(x) = 3x^2-10x+2 find the vertex of y=f(x+4)-5
allochka39001 [22]

3 {(4 + x)}^{2}  - 10(x + 4) + 2 - 5
so
3( {x}^{2}  + 8x + 16) - 10x - 40 + 3
so
3 {x}^{2}  + 14x + 11
take differential calculus
6x + 14 = 0
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3 0
4 years ago
A person drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 200 times. Here are the observed f
Olin [163]

Answer:

\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7

Now we can calculate the degrees of freedom for the statistic given by:

df=6-1=5

And we can calculate the p value given by:

p_v = P(\chi^2_{5} >6.7)=0.244

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that  the outcomes are equally likely

Step-by-step explanation:

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the frequencies

H1: There is a difference in the frequencies

The level of significance assumed for this case is \alpha=0.01

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The observed values are:

Value            1     2    3    4    5     6

Frequency  26  32  44  37  27  34

And the expected values are for this case the same E_i = \frac{200}{6}= 33.33

And now we can calculate the statistic:

\chi^2 = \frac{(26-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33}+\frac{(44-33.33)^2}{33.33}+\frac{(37-33.33)^2}{33.33}+\frac{(27-33.33)^2}{33.33}+\frac{(34-33.33)^2}{33.33}=6.7

Now we can calculate the degrees of freedom for the statistic given by:

df=6-1=5

And we can calculate the p value given by:

p_v = P(\chi^2_{5} >6.7)=0.244

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we can conclude that  the outcomes are equally likely

7 0
4 years ago
Questions on attached photo.<br>​
Vinil7 [7]

Answer:

0

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I need to know the answer please help me
spin [16.1K]
First is 42 and the second is 4.5
6 0
2 years ago
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