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Tema [17]
3 years ago
6

Help me to solve this​

Computers and Technology
2 answers:
Ymorist [56]3 years ago
8 0

Answer:

the answer is :

1-4

2-5

3-1

4-3

5-2

dedylja [7]3 years ago
7 0

Answer:

Hello!

Mouse-points and selects gui objects

Printer-it produces hard copy output

Alu- performs mathematical calculations

Rom-the instructions stored in it cannot be changed by the user

pendrive- can be considered as a small external hard disk

P.S. please follow me and also mark me as the brainliest ;)

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Which type of attack modifies the fields that contain the different characteristics of the data that is being transmitted?
tatuchka [14]

Answer:

An HTTP Header attack

Explanation:

In web applications an HTTP refers to Hypertext Transfer Protocol and an HTTP Header is the value that is displayed in  a request or response message, the header has a name and a value separated by a colon.

An HTTP header attack called an header injection is a vulnerability that is present when users' inputs are required for the dynamic generation of HTTP headers. This vulneraility allows several security threats to be carried out, some examples are:

  1. Malicious site redirection
  2. Cross-site scripting, and
  3. Session fixation through the set-cookie header
8 0
3 years ago
In the table below identify the data type that would be most suitable for the second field
marishachu [46]

Answer:

C.

Explanation:

The second field is Age. Age is expressed as a number so will most likely be stored in a number data type.

6 0
3 years ago
State four features of information​
Xelga [282]

Answer:

This is your answer

8 0
3 years ago
In high-tech fields, industry standards rarely change.<br> True <br> False
Sophie [7]

Answer: false

Explanation:

5 0
2 years ago
WRITE A JAVA PROGRAM TO PRINT THE PATTERN<br> 13579<br> 2468<br> 357<br> 46<br> 5
Inessa05 [86]

Answer:

import java.util.Scanner;

import java.lang.*;

class Main

{

  public static void main(String args[])

  {

     int n;

     //For capturing the value of n

     Scanner scanner = new Scanner(System.in);

     System.out.println("Enter the value of n:");

     //The entered value is stored in the var n

     n = scanner.nextInt();

     int k=1;

     printnum(n,k);  

  }

  public static void printnum(int n,int k)

  {

       if(n%2==0)

       {

       for(int i=k;i<=n-1;i=i+2)

            {

                System.out.print(i);

            }    

        System.out.println("");

       }

       else

        {

       for(int i=k;i<=n-1;i=i+2)

            {

                System.out.print(i);

            }    

        System.out.println("");

        }

      n--;

      if(n<=1)

      {

         System.exit(0);

      }

      else

      {

          printnum(n,k+1);

      }

   }

}

Explanation:

The program is self explanatory.

4 0
3 years ago
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