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elena-14-01-66 [18.8K]
3 years ago
15

A padock measures 100m x 150m . how many times does jo need to run around it to go 3km?

Mathematics
2 answers:
mylen [45]3 years ago
5 0

SIZE

400

UNIT OF MEASURE

meters

BASED ON LANE

1

To begin, you must do Steps 1-3 to enter (or verify) the correct information for the track being used. Frequently-used values have been pre-entered in all three steps. Change them only if required.

Step 1. ENTER THE TRACK SIZE (i.e., the distance covered when completing one lap - normally in Lane 1) and select the unit of measure.

 most outdoor tracks are either 400 meters or 440 yards (4 laps to a mile)

 most indoor tracks are either 200 meters or 220 yards (8 laps to a mile)

See NOTE 3 for determining track size. Also note that a very small number of tracks use a lane other than Lane 1 to define the track size (see NOTE 4). If the size you entered is not based on Lane 1, select the lane number upon which the size is based.

Step 2. ENTER THE LANE WIDTH of lanes on the track (they should all be the same width). While the best tracks (IAAF, Olympic, etc.) have lanes that are 1.22m to 1.25m wide, most high school and college tracks have lane widths measured in inches (e.g., 42"). See NOTE 5 for information on how to measure lane width. LANE WIDTH

42

Step 3. IS THERE A RAISED CURB on the inside of Lane 1 (normally 2" - 2.5" high)? If there is, select "yes." If the inside edge of Lane 1 is defined only by a painted line, select "no." See NOTE 6 for further information about curbs.

no

Now that you have completed Steps 1 - 3, select a calculation section below, enter the requested parameter(s), and click on the "click here" calculation button for that section. After noting (or printing) the results, enter different parameters for the same calculation or proceed to another calculation section.

ANWERS: 42  

san4es73 [151]3 years ago
4 0

Answer:

Six times.

Step-by-step explanation:

Find the perimeter: 100+100+150+150= 500 m all the way around

3 km = 3000 m

3000 divided by 500 is 6 times.

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<u>Solution-</u>

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As all the lights start out off, in the first pass all bulbs will be turned on.

In the second pass all the multiples of 2 will be off and rest will be turned on.

In the third pass all the multiples of 3 will be off, but the common multiple of 2 and 3 will be on along with the rest. i.e all the multiples of 6 will be turned on along with the rest.

In the fourth pass 4th light bulb will be turned on and so does all the multiples of 4.

But, in the sixth pass the 6th light bulb will be turned off as it was on after the third pass.

This pattern can observed that when a number has odd number of factors then only it can stay on till the last pass.

1 = 1

2 = 1, 2

3 = 1, 3

<u>4 = 1, 2, 4</u>

5 = 1, 5

6 = 1, 2, 3, 6

7 = 1, 7

8 = 1, 2, 4, 8

9 = 1, 3, 9

10 = 1, 2, 5, 10

11 = 1, 11

12 = 1, 2, 3, 4, 6, 12

13 = 1, 13

14 = 1, 2, 7, 14

15 = 1, 3, 5, 15

16 = 1, 2, 4, 8, 16

so on.....

The numbers who have odd number of factors are the perfect squares.

So calculating the number of perfect squares upto 1800 will give the number of light bulbs that will stay on.

As,  \sqrt{1800} =42.42  , so 42 perfect squared numbers are there which are less than 1800.

∴ 42 light bulbs will end up in the on position. And there position is given in the attached table.

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