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3 years ago

Help me please I’m so confused ):

Mathematics

1 answer:

Marrrta [24]3 years ago

4 0

The domain is all the x-values you can use with this function. When dealing with a function like this, you need to ask yourself, what would make the bottom equal to 0? Whatever those numbers are, you do NOT want them in your domain.

A fundamental rule is that you cannot divide by 0 or have 0 as a denominator.

So, you solve x^2+6x=0 to find that x=0 or x=-6 would make the denominator 0.

The domain is everything BUT those two values, because they essentially break your function.

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While walking from her house to school, Miriam walks at a pace of 5 km/h. When she walks in the hallways at school, she slows do

lubasha [3.4K]

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4 years ago

Scores on a national math test are Normally distributed, with a mean score of 490 and a standard deviation of 50. Which test sco

alisha [4.7K]

Answer:

532

Step-by-step explanation:

The score that represents the top 20% = A score = 80%

Z score for 80% percentile = 0.842

We solve using the z score formula

z = (x-μ)/σ, where

x is the raw score = ??

μ is the population mean = 490

and σ is the population standard deviation = 50

Hence:

0.842 = x - 490/50

Cross Multiply

0.842 × 50 = x - 490

x = 0.842 × 50 + 490

x = 42.1 + 490

x = 532.1

Approximately = 532

Therefore, the test score = 532

7 0

3 years ago

Read 2 more answers

2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).

alexandr1967 [171]

Given: F=ma. To solve for a, we isolate a on one side of this equation. To do this, divide both sides of F=ma by m. Then F/m = a.

Thus, if m=10 units, the acceleration is a = F/10 units. Looks as tho' you were given the numeric value of F but did not share that value here.

Solving F=ma for m: m=F/a. Thus, if F=25 units and a=5 units, m=25/5 units, or m=5 units.

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3 years ago

Read 2 more answers

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Lunna [17]

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4 years ago

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Lynna [10]

Hey! Thanks for using Brainly.

Could you add a attachment or the question so we can know the two notes in the question? Once you do that I can assist you further.

Looking forward to hear your response.

Have an amazing day! :)

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4 years ago