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Iteru [2.4K]
3 years ago
13

The length of a rectangle is twice its width. The perimeter of the rectangle is 126 feet.

Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer: Length = 42ft Width = 21ft

Step-by-step explanation:

Let "w" be width

W = 21ft

w x 2 = L

L = 42ft

Perimeter:

42+42+21+21

=126

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Tickets for a school play sold for $7.50 for each adult and $3.00 for each child. The total receipts for 118 tickets totaled $69
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X= number of adult tickets
y=number of child tickets.
we can suggest this system of equations: 
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7.5x+3y=696

we can solve this system of equations by substitution method:
7.5(118-y)+3y=696
885-7.5y+3y=696
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y=-189/-4.5
y=42

x=118-y
x=118-42
x=76

Answer: the number of adult tickets sold was 76. 
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Show the graph of -3x + 10
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Describe the correlation between the number of a miles driver logs and the drivers age
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The Friendly Sausage Factory (FSF) can produce hot dogs at a rate of 5,750 per day. FSF supplies hot dogs to local restaurants a
NARA [144]

Answer:

A) 22812 hotdogs per run

B) 75 runs/yr

C) 4 days in a run

Step-by-step explanation:

We are given;

Production rate;p = 5750 per day

Steady Usage rate;u = 270 per day

Setup cost of hotdog;S = $67

Annual carrying cost (H) = 47 cents = $0.47 per hot dog

No. of Production days; d = 297 days

A) Let's first find the annual demand given by the formula;

Annual demand;D = pd

D = 5750 × 297

D = 1707750 hot dogs/yr

Now, formula for optimal run size is given by;

Q_o = √[(2DS/H) × (p/(p - u))]

Plugging in the relevant values gives;

Q_o = √[(2 × 1707750 × 67/0.47) × (5750/(5650 - 270))]

Q_o =√520375454.7971209

Q_o = 22812 hotdogs per run

B) formula for Number of runs per year is given as;

No. of Runs = D/Q₀

Thus;

no. of runs = 1707750/22812

no. of runs ≈ 75 runs/yr

C) Length of a run is given by the formula;

Length = Q₀/p

Length = 22812/5750

Length ≈ 4 days in a run

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3 years ago
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