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2 years ago

A^15/a^5=a^10 true or false

Mathematics

2 answers:

ad-work [718]2 years ago

8 0

Answer:

true

Step-by-step explanation:

a^15 ÷ a^5 = a^10

a÷a = a

15- 5 =10

give brainliest please I need it to level up

galben [10]2 years ago

8 0

Answer:

True

Step-by-step explanation:

Using the rule of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , then

$\frac{a^{15} }{a^{5} }$

= $a^{(15-5)}$

= $a^{10}$

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Step-by-step explanation:

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3 years ago

HELP ASAP will give BRAINLIEST

tester [92]

Hey there! I'm happy to help!

The question tells us that m∠JKL is 54. We see from the diagram that this is the combination of the angles m∠JKM and m∠MKL. So, we can combine their values, which are equal to 54 to find x.

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2 years ago

Calculate the perimeter of a rectangle with length 4+5y-3x and width 2x - 8y

ICE Princess25 [194]

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Step-by-step explanation:

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3 years ago

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Find all solutions to the equation (x² + 5x + 6)(x² − 3x − 4) = 0.

Soloha48 [4]

Answer:

The solutions are:

$x=-2,\:x=-3,\:x=-1,\:x=4$

Step-by-step explanation:

To find the solutions to the equation $\left(x^2+5x+6\right)\left(x^2-3x-4\right)=0$ you need to:

Factor $\left(x^2+5x+6\right)$

Break the expression into groups

$x^2+5x+6=\left(x^2+2x\right)+\left(3x+6\right)$

Factor out $x$ from $(x^2+2x)$

$x^2+2x=x\left(x+2\right)$

Factor out 3 from $3x+6$

$3x+6=3\left(x+2\right)$

$x^2+5x+6=x\left(x+2\right)+3\left(x+2\right)\\\\\mathrm{Factor\:out\:common\:term\:}x+2\\\\x^2+5x+6=\left(x+2\right)\left(x+3\right)$

Factor $\left(x^2-3x-4\right)$

$x^2-3x-4=\left(x^2+x\right)+\left(-4x-4\right)\\\\x^2-3x-4=x\left(x+1\right)-4\left(x+1\right)\\\\x^2-3x-4=\left(x+1\right)\left(x-4\right)$

Therefore

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Step-by-step explanation:

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