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Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
Answer:
$347.45
Step-by-step explanation:
total = tickets + parking + t shirt + meal
tickets = 250 + 6% tax
6% tax is of 250, so this is equal to
250 + 6% of 250
6% = 0.06 because we divide by 100 to convert to a decimal from a percentage
thus, tickets = 250 + 0.06 of 250 = 250 * 1 + 0.06 * 250 + 1.06 * 250 = 265
parking = 20
use a similar strategy from the tickets and apply that to the t shirt
t shirt = 35 + 7 % tax = 35 + 0.07 * 35 = 1.07 * 35 = 37.45
meal = 25
total = 265 + 20 + 37.45 + 25 = $347.45
What r the following questions?