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Snezhnost [94]
3 years ago
5

∠2= ∠5 , because they are

Mathematics
1 answer:
Contact [7]3 years ago
3 0

\sf  \red {alternate \: angles}

\huge \purple{ \underbrace{ \overbrace{Hope \:  it \:  helps}}}

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(2c^{-5})^{3} simplify ​
andrew-mc [135]

Answer:

Step-by-step explanation:

If this is

(2c^{-5})^3 then you distribute the 3 to both terms inside the parenthesis (the 2 and the c^-5).  2 cubed is 8.  The rule for the power to power is that you multiply the powers together to get -15.  So the final simplification is

8^{-15}

6 0
3 years ago
What is correct in these ordered pairs (4,9) and (4,-9)?
timurjin [86]

Answer:

(maaf kalau salah

THANKS

4 0
2 years ago
How do I find the mean of these numbers
pshichka [43]

Answer:

add all of them together (x and y’s) the divide the sum by the amt of numbers

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which of these is equivalent to 1 over x to the power of 5 ? 1 fifth x negative x to the power of 5 x to the power of 5 x to the
Kisachek [45]

Answer:

x^-5 = x to the power of negative 5

Step-by-step explanation:

Which of these is equivalent to 1 over x to the power of 5 ?

Mathematically this is expressed as

(1/x)⁵

We have a rule when it comes to expressing power

(1/a)^b = a^-b

Hence, applying this rule to our question

(1/x)⁵ = (1/x)^5

= x^-5

This is written in words as:

x to the power of negative 5

5 0
3 years ago
Increasing the sample size while keeping the same confidence level has what effect on the margin of error? A. Increases the marg
DiKsa [7]

Answer:

C. Decreases the margin of error and hence increases the precision

Step-by-step explanation:

If we select a sample by Simple Random Sampling in a population of “infinite” size (a population so large that we do not know its size exactly), then the margin of error is given by

\bf E=\frac{ZS}{\sqrt{n}}

where  

<em>Z = The Z-score corresponding to the confidence level </em>

<em>S = The estimated standard deviation of the population </em>

<em>n = the size of the sample. </em>

As we can see, since n is in the denominator of the fraction and the numerator is kept constant, the larger the sample size the smaller the margin of error, so the correct choice is:

C. Decreases the margin of error and hence increases the precision

4 0
3 years ago
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