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3 years ago

∠2= ∠5 , because they are

Mathematics

1 answer:

Contact [7]3 years ago

3 0

$\sf \red {alternate \: angles}$

$\huge \purple{ \underbrace{ \overbrace{Hope \: it \: helps}}}$

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Which relation is a function??????

kap26 [50]

Answer:

Step-by-step explanation:

there cannot be 2 different points on the same x coordinate

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2 years ago

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Put the following equation of a line into slope-intercept form, simplifying all

Pepsi [2]

Answer:

$4y = 16-2x\\y = \frac{16}{4} - \frac{2x}{4}\\ y = \frac{-1x}{2}+4\\y = 0.5x+4$

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4 years ago

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The given line segment has a midpoint at (−1, −2).

Bas_tet [7]

Answer:

The given line segment has a midpoint at (−1, −2).

On a coordinate plane, a line goes through (negative 5, negative 3), (negative 1, negative 2), and (3, negative 1).

What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?

y = −4x − 4

y = −4x − 6

y = One-fourthx – 4

y = One-fourthx – 6

y = Three-halvesx + 1

8 0

4 years ago

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Plz, help me with this question!

sergey [27]

Answer:

I think D is right, because usually congruent angles have the same angle measure, and there's no answer choice for 1 and 3.

7 0

3 years ago

Write the equation of the line that is parallel to y = -x – 5 and has a y-intercept at (0, 11).

FrozenT [24]

Answer:

$y=-x+11$

Step-by-step explanation:

We know that the new equation must be parallel to $y=-x-5$ .

Therefore, since they are parallel, the slope of the new equation must be the same as the old.

The slope of the original equation is -1.

Therefore, the slope of our new equation is also -1.

We also know that it has a y-intercept at (0, 11).

And as determined earlier, it has a slope of -1.

So, we can use the slope-intercept form:

$y=mx+b$

Where m is the slope and b is the y-intercept.

We will substitute -1 for m and 11 for b. Thus, our equation is:

$y=-x+11$

8 0

3 years ago