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koban [17]
2 years ago
14

Find the Quotient and Remainder. 5x^3 - 6x^2 + x + 7 divided by x^2

Mathematics
1 answer:
12345 [234]2 years ago
5 0

Step-by-step explanation:

Solution

According to remainder theorem, when f(x) is divided by (x+2), Remainder =f(−2)

f(x)=5x3+2x2−6x+12

f(−2)=5(−2)3+2(−2)2−6(−2)+12

=5×−8+2×4+12+12

=−40+32=−8

∴ Remainder=−8

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2 ÷ 48.9 plss need help
Mkey [24]

Answer:

0.04

I rounded to one significant figures.

3 0
3 years ago
consider the graph of the following qudratic equation. y= -x^2 -10x + 24.What is the y-value of the vertex?
3241004551 [841]

Given that the quadratic equation is y=-x^{2}-10 x+24

We need to determine the y - value of the vertex.

<u>The x - value of the vertex:</u>

The x - value of the vertex can be determined using the formula,

x=-\frac{b}{2 a}

where a=-1, b=-10, c=24

Substituting these values, we get;

x=-\frac{(-10)}{2(-1)}

Simplifying the terms, we get;

x=-\frac{-10}{-2}

x=-5

Thus, the x - value of the vertex is -5.

<u>The y - value of the vertex:</u>

The y - value of the vertex can be determined by substituting the x - value of the vertex ( x = -5) in the equation y=-x^{2}-10 x+24

Thus, we get;

y=-(-5)^{2}-10(-5)+24

Simplifying the values, we have;

y=-25+50+24

y=49

Thus, the y - value of the vertex is 49.

8 0
2 years ago
Find the sum: (x + 3) + (4x - 1)
Sliva [168]

Answer:

the answer is 5x + 2. I hoped that worked

5 0
3 years ago
Simplify log(16x²) ± 2㏒(1÷×)
sp2606 [1]

Answer: just simplify condense it then your answer will be log(16)

8 0
2 years ago
1. Which would be a more helpful for solving the system: adding the two equations or subtracting
ira [324]

Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

\frac{2x+1}{2y}=7\\\\

Equation 2:

\frac{6x-1}{2y}=5

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\  with\ 6\\\\12x+6=84y

Now for the second equation:

\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y

Now subtracting equation 2 from equation 1

12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y

now insert this value of y into any equation

lets insert it into equation 1

\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375

5 0
3 years ago
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