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Sholpan [36]
3 years ago
5

Which is equivalent to 49 3/2

Mathematics
1 answer:
Korolek [52]3 years ago
5 0
49^{\frac{3}{2}}=(7^2)^{\frac{3}{2}}=7^3=343
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Find the sum of ∑4/k=1 (-4k)
Annette [7]

Answer:

Hello,

Answer C: -40

Step-by-step explanation:

\displaystyle \sum_{k=1}^4\ (-4k)\\\\=-4*\sum_{k=1}^4\ k\\\\=-4*4*\dfrac{1+4}{2} \\\\=-4*5*2\\\\=-40\\

4 0
3 years ago
Can some one help me in this problem
strojnjashka [21]
I believe x=116 and z=26. 4z-40=64
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8 0
3 years ago
G = cst (solve for s)
Harrizon [31]

Step-by-step explanation:

Simplifying

g = cst

Solving

g = cst

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Simplifying

g = cst

7 0
3 years ago
Can someone help me figure out what is 5/12 of 1 ⅓ =
lorasvet [3.4K]

Answer:

Gotta multiply them

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?
Rashid [163]

Answer:

R-{13}

Step-by-step explanation:

We are given that

f(x)=x+7

g(x)=\frac{1}{x-13}

We have to find the domain of fog(x).

fog(x)=f(g(x))

fog(x)=f(\frac{1}{x-13})

fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}

Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

6 0
3 years ago
Read 2 more answers
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