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Sholpan [36]
3 years ago
5

Which is equivalent to 49 3/2

Mathematics
1 answer:
Korolek [52]3 years ago
5 0
49^{\frac{3}{2}}=(7^2)^{\frac{3}{2}}=7^3=343
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tresset_1 [31]
Since it’s not x3 it must be +8 so if i were you i’d pick B
7 0
2 years ago
What is the value of y in the equation y − 7 = 21? (4 points)
labwork [276]

Answer:

4

Step-by-step explanation:

y-7=21

+7 +7

y=21+7

y=28

8 0
2 years ago
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in addition to dog walking on Tuesday Eric made $45 dog sitting at one of his customers homes if he made $168 on Tuesday right i
Rus_ich [418]

Since we don't know how much Eric makes per dog, let's let <em>x </em>represent that value. Let's also let <em>y</em> represent our answer.

First, let's consider the two numbers we KNOW will be in the equation. The 56 that Eric made dog sitting and the 168 he made in total on Tuesday. Now, we're going to need to use subtraction and division in this equation.

(168 - 45) ÷ <em>x</em> = <em>y</em>


Hope this answer helped you out. :)

8 0
2 years ago
Political party affiliation is believed to be a very strong indicator of how voters will vote in Presidential Elections. You are
Norma-Jean [14]

Answer:

The best conclusion is that we are 90% that the true population proportion of Republicans that voted for Mitt Romney is between 0.7273 and 0.8106.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

The 90% confidence interval for the proportion of Republican voters that had voted for Mitt Romney is (0.7273, 0.8106). The best conclusion is that we are 90% that the true population proportion of Republicans that voted for Mitt Romney is between 0.7273 and 0.8106.

7 0
2 years ago
If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?
Volgvan

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are c(x) = \frac{5}{x - 2} and d(x) = x + 3

So, (cd)(x) = (\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}

Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.

Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)

8 0
3 years ago
Read 2 more answers
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