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dedylja [7]
3 years ago
7

What are the missing coefficients for the chemical equation

Chemistry
1 answer:
aniked [119]3 years ago
8 0

Answer:

2C2H2 + 5O2 → 4CO2 + 2H2O

Explanation:

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Calculate the pH during the titration of 30.00 mL of 0.1000 M HCOOH(aq) with 0.1000 M NaOH(aq) after 29.3 mL of the base have be
pashok25 [27]

Answer:

3.336.

Explanation:

<em>Herein, the no. of millimoles of the acid (HCOOH) is more than that of the base (NaOH).</em>

<em />

So, <em>concentration of excess acid = [(NV)acid - (NV)base]/V total</em> = [(30.0 mL)(0.1 M) - (29.3 mL)(0.1 M)]/(59.3 mL) = <em>1.18 x 10⁻³ M.</em>

<em></em>

<em> For weak acids; [H⁺] = √Ka.C</em> = √(1.8 x 10⁻⁴)(1.18 x 10⁻³ M) = <em>4.61 x 10⁻⁴ M.</em>

∵ pH = - log[H⁺].

<em>∴ pH = - log(4.61 x 10⁻⁴) = 3.336.</em>

7 0
4 years ago
What Type of Reaction is the following: lithium carbonate → lithium oxide + carbon dioxide
valentinak56 [21]

Answer: 2. Decomposition

Explanation:

Synthesis reaction is a type of chemical reaction in which two reactants combine to give a single product.

Decomposition reaction is defined as the reaction where a single substance breaks down into two or more simpler substances.

lithium carbonate → lithium oxide + carbon dioxide

LiCO_3\rightarrow LiO+CO_2

Single replacement reaction is a type of chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

A double replacement reaction is one in which exchange of ions take place.

5 0
4 years ago
So2 (5.00 g) and co2 (5.00 g) are placed in a 750.0 ml container at 50.0 °c. the partial pressure of so2 in the container was __
aliya0001 [1]
To calculate the partial pressure, we have to calulate the total pressure first.
Total pressure = (nRT/V)SO2 + (nRT/V)CO2
n is the number of moles
R is the general gas constant = 0.0821 L.atm/K.mole
T is the temperature in Kelvin
V is the total volume
n SO2 = mass/molar mass = 5/ 32 + 16*2 = 0.078125
n CO2 = mass/molar mass = 5/14+ 16*2 = 0.1
T = 50+273 = 323K
V = 750/1000 = 0.75 liters
Total Pressure = (0.078125*0.0821*323/0.75) + (0.1*0.0821*323/0.75) = 2.7623 + 3.535 = 6.298 atm
Partial pressure = x SO2 * Total Pressure = (no. of moles of SO2 / total no. of moles) * Total pressure = (0.078125/0.078125+0.1) * 6.298 = 2.762 atm.
4 0
4 years ago
Read 2 more answers
Describe how chemists use mass as a way of getting a precise estimate of the number of entities in a sample.
jok3333 [9.3K]

Answer:

Explanation:

To start with, the mass of a substance is centered on the amount of particles contained in it.

Mass of a substance measure is the same anywhere it is taken.

In chemistry, the concept of mole is used to find the exact estimate of  the number of entities in a sample.

A mole of substance is quantity that is used to express the number of particles contained in it.

  1 mole of any substance contains the Avogadro's number of particles.

This amount of particles is given as 6.02 x 10²³; the particles can be protons, neutrons, electrons e.t.c.

To find the number of moles;

        Number of moles  = \frac{mass}{molar mass}

       Through this, we clearly ascertain the number of entities in a sample given the mass.

5 0
3 years ago
A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600.mL at 1.0atm. To prepare for ignition of
Ket [755]

12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.

Explanation:

Data given:

The air fuel mixture is assumed to be having ideal behaviour

initial volume of gaseous air fuel mixture V1 = 600 ml

initial pressure of gaseous air fuel mixture P1= 1 atm

final volume when piston is removed, V2= 50 ml

final pressure of the gaseous air mixture, P2 = ?

Applying the Boyle's Law,

P1V1 = P2V2

rearranging the equation:

P2 = \frac{P1V1}{V2}

putting the value in the equation,

P2 = \frac{600 X 1}{50}

P2 = 12 atm

the pressure is increased to 12 atm when volume is reduced to 50 ml.

7 0
4 years ago
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