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dedylja [7]
3 years ago
7

What are the missing coefficients for the chemical equation

Chemistry
1 answer:
aniked [119]3 years ago
8 0

Answer:

2C2H2 + 5O2 → 4CO2 + 2H2O

Explanation:

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Iron is found in Earth's crust as several iron compounds. Calculate the mass in kilograms of the amount of each of the following
notka56 [123]

The mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.

<h3>What are iron ores?</h3>

Iron ores refers to minerals in which iron occur in combined form found in the earth's crust.

Some ores of iron include:

  • hematite,
  • magnetite,
  • limonite, and
  • siderite.

Molar mass of hematite, Fe₂O₃ = 160 g/mol

Molar mass iron = 56 g/mol

Percent mass of iron in hematite = 56/160 = 35%

The mass of hematite that contains 8.0×10³ kg of iron = 8.0 × 10³kg/0.35 = 2.29 × 10⁴ kg.

Therefore, the mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.

Learn more about iron ores at: brainly.com/question/4693242

#SPJ1

3 0
2 years ago
Do anybody knows this I need help asap
Elza [17]

Transform is the answer and also to save you points search the question on here before you ask it because this question has been asked and answered.


6 0
3 years ago
Pentaborane-9,
frozen [14]

Given question is incomplete. The complete question is as follows.

Pentaborane (B_{5}H_{9}) is a colorless highly reactive liquid that will burst into flames when exposed to oxygen.the reaction is:

  2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)

Calculate the kilojoules of heat released per gram of the compound reacted with oxygen.the standard enthalpy of formation B_{5}H_{9}(l) , B_{2}O_{3}(s), and H_{2}O(l) are 73.2, -1271.94, and -285.83 kJ/mol, respectively.

Explanation:

As the given reaction is as follows.

   2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)

Therefore, formula to calculate the heat energy released is as follows.

       \Delta H = \sum H_{products} - \Delta H_{reactants}

Hence, putting the given values into the above formula is as follows.

         \Delta H = \sum H_{products} - \Delta H_{reactants}

     = 5 \times (-1271.94 kJ/mol) + 9 \times (-285.83 kJ/mol) - 2 \times (73.2 kJ/mol) - 12(0)

     = -9078.59 kJ/mol

Since, 2 moles of Pentaborane reacts with oxygen. Therefore, heat of reaction for 2 moles of Pentaborane is calculated as follows.

        \frac{\Delta H}{2 \times \text{molar mass of pentaborane}}      

         \frac{-9078.59 kJ/mol}{2 \times 63.12 g/mol}

                  = -71.915 kJ/g

Thus, we can conclude that heat released per gram of  the compound reacted with oxygen is 71.915 kJ/g.

8 0
3 years ago
Answer from this picture.
Ganezh [65]
Try photo math it will probably be more helpful
7 0
4 years ago
Please help ASAP. I'm stuck on this one question. &gt;.&lt;
Elenna [48]

C. A compound !hope this helps!

7 0
4 years ago
Read 2 more answers
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