Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
![A= \frac{LM+KN}{2} *MP= \frac{10+20}{2} *10=150](https://tex.z-dn.net/?f=A%3D%20%5Cfrac%7BLM%2BKN%7D%7B2%7D%20%2AMP%3D%20%5Cfrac%7B10%2B20%7D%7B2%7D%20%2A10%3D150)
sq. units.
Answer:
the probability of flipping n times is 12n, since that's the probability of flipping exactly n−1 tails followed by 1 heads.
Step-by-step explanation:
Rate of change=(changespeed)/(changetime)=(s1-s2)/(t1-t2)
change is (0-60)/(0-5)=-60/-6=12
answer is 12 units per second