(y-k)²/a² + (x-h)²/b² = 1
Vertices being : A(0,1) & B(0, - 9), means that h=0
Let's calculate k: Af₁ + Af₂ = |2+8| = 2a = 10 → a=5 (f₁ and f₂ = focii)
1) a = 10 (WRONG) since a =5
2) h=3 (WRONG) since h =0
3) k =0 (WRONG) since k =5
4) b = 4 RIGHT; PROOF:
we know that : c² = a² - b²
c= 3 & a = 5 then → 3² = 5² - b²
9 = 25 - b²
b² = 25-9 = 16 and b = 4
Answer: 5
Step-by-step explanation:
Range = highest value - lowest value
The highest value from the data set given = 1
The lowest value = -4
Therefore :
Range = 1 - (-4)
Range = 1 + 4
Range = 5
Answer:
proportional
Step-by-step explanation:
If they were all the same number, then each one would be 1/3 of 57. That's 19. All three integers would be 19 ... an odd integer. All you have to do is take 2 away from one of them and glue it onto another one of them, and you'll have your three consecutive odd integers.
You can fit 3 in there 13 whole times. After you do that,
the 40 is not quite full yet, but it only has room for 1 more,
so you cannot stuff the whole 3 in there again.