Answer: A
Compound interest simply defined as the interest added at regular interval. Compound interested can be calculated using
Compound interest = P (1+) ^nt and Pe ^rt
P = Initial balance
r = Annual interest rate
n = Number of times the interest is compounded per year
t =Number of year money is invested
Using
Compound interest = P (1+ ) ^nt
Continuous
P= $ 8000
t = 6
r = 6.25%
=
= 0.0625
n = 1
Compound interest = 8000 (1+) ^1×6
= 8000 (1 + 0.0625) ^6
= 8000 (1.0625) ^ 6
= 8000× 1.4387
= $11,509.6
Semi- annually
P= $ 8000
t = 6
r = 6.3%
=
= 0.063
n = 2
Compound interest = 8000 (1+) ^2×6
= 8000 (1 + 0.063) ^12
= 8000 (1.063) ^12
= 8000× 1.4509
= $11,607.0
Investing $ 8000 semi-annually at 6.3% for 6 years yields greater return
Therefore the answer is (A)
The horizontal asymptote of the function is the minimum number of deer in the area.
- The equation of horizontal asymptote is:

- The horizontal asymptote means that, the number of deer will never be less than 40
The equation is given as:

Expand the numerator

Cancel out the common factor

Hence, the equation of horizontal asymptote is:

The horizontal asymptote means that, the number of deer will never be less than 40
Read more about horizontal asymptotes at:
brainly.com/question/4084552
Answer:
AE=22.4
Step-by-step explanation:
BE is 1/2 of BC
BC is 20 cm All sides of a square are equal
BE = 1/2 BC Property of a midpoint.
BE = 10
Now just use Pythagorus
AB^2 + BE^2 = AE^2
AE^2 = 20^2 + 10^2 Perform the sqrs
AE^2 = 400 + 100 Add the terms
AE^2 = 500 Take the square root of both sides
√AE^2 = √500
AE = 22.36
AE ≈ 22.4
46.2*(10-2)
10-2=8
46.2*8=369.6
Your answers listed doesnt follow along the order of pemdas. im not sure how those are the answers for that equation.