I need the answers?

Mathematics

1 answer:

tresset_1 [31]2 years ago

5 0

The y intercept is -5

You might be interested in

write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)

gladu [14]

Find midpoint of segment.
(-1,1), (7,-5)
$x= \frac{-1+7}{2}=3,y= \frac{1+(-5)}{2}=-2$

Find slope of line which passes through (-1,1) and (7,-5).
$m= \frac{-5-1}{7-(-1)}= \frac{-6}{8}=- \frac{3}{4}$

The slope of perpendicular line is negative reciprocal value of m.
$m_{\perp}=- \frac{1}{m} =- \frac{1}{- \frac{3}{4} } = \frac{4}{3}$

Write quation of line which slope is $\frac{4}{3}$ and passes throug the point (3,-2).
$m=\frac{4}{3},x_1=3,y_1=-2
\\y-y_1=m(x-x_1)
\\
\\y-(-2)=\frac{4}{3}(x-3)
\\
\\y+2=\frac{4}{3}x-\frac{8}{3}
\\
\\3y+6=4x-8
\\4x-3y-14=0$

3 0

3 years ago

Hello I need help thanks!

prisoha [69]

Answer:

$36

Step-by-step explanation:

ok so first you want to find out how much she makes per hour and to do that you would take $27 / 3hrs = $9. So now we know that Kayla makes $9 per hour. If she babysits for 4 hours you would then do $9 x 4hr = $36.

8 0

3 years ago

What is the distance between nicholas's school and the post office?

aleksklad [387]

Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

$d= \sqrt{(-2-3)^2+(-2-2)^2} \\ \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16} \\ \\ \sqrt{41} =\bold{6.4} \ units$

Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

$d= \sqrt{(1-(-3))^2+(-1-2)^2} \\ \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9} \\ \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}$