You should use a calculator for this type of problem, but the answer would be 6.816
Answer:
D. ∠E ≅ ∠N
Step-by-step explanation:
The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...
∠E ≅ ∠N
Then the SAS congruence postulate can be claimed.
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<em>Additional comment</em>
The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.
There will be 42 in each row with 2 left over
Let

be the amount of parts the student answered correctly. Suppose that

is a function between

and the score of a student's project. As the student initially receives a fixed

points for turning the project in and

points for each correct part, the function is initially:

When the students receive

points for each correct part, the coefficient of

changes, as the amount of points received per correct answer increases. Thus:

.
The answer is x=-20.
6+ -28 -x =-2
You first add 28 to each side=6+-x=26 then you minus 6 from each side=-x=20.
Then you divide 20 by -x resulting in x=-20