What is square route of 4

You can make the mixed number 5 2/3 an improper fraction, which is the number in the numerator is larger than the number in the denominator.
Multiply, Add, and Keep the denominator are the steps you need to take.
Multiply the denominator by the whole number and then add the number in the numerator, while keeping the denominator. 5*3+2=17>>> 17/3 is the improper fraction.
17/3 ÷ 2 is the resulting equation.
When you divide fractions, you have to multiply by the reciprocal. 2/1 is the whole number 2, but in fraction form. The reciprocal is 1/2 because your just flipping the numerator and the denominator.
17/3 * 1/2 is the new equation.
When you multiply fractions, you multiply straight across.
17/3 * 1/2 = 17/6 or 2 5/6 is your answer.

8 0

3 years ago

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

7 0

4 years ago

Read 2 more answers

Please help with math question!!

vredina [299]

Answer:

b. cubic

Step-by-step explanation:

hope this helps :)

6 0

3 years ago