Answer:
50 grams
Step-by-step explanation:
Let the amount of cheese required by the recipe be "x"
Ann increased 60% from original amount and then used up 80 grams. Thus:
<em>Original, increased by 60%, became 80</em>
<em />
This translated to algebraic equation would be:
x + 0.6x = 80
<u>Note:</u> 60% = 60/100 = 0.6
So we can solve the above equation for "x" and get our answer. Shown below:
Hence,
the recipe required 50 grams of cheese
Answer:
x = 129.8 degrees, y = 50.2 degrees, x + y = 180
Step-by-step explanation:
Let's say you have 2 supplementary angles, x and y
So x + y = 180
if x is 79.8 degrees less than the measure of a supplementary angle, then x = y - 79.8
Putting this into our x + y = 180 equation, we get
(y - 79.8) + y = 180
2y - 79.8 = 180
2y = 180 + 79.8
2y = 259.8
y = 259.8/2 = 129.9 degrees.
so x = 129.9 - 79.6 = 50.3 degrees.
See if it worked. x = 129.9 degrees, y = 50.3 degrees, x + y = 180 so we found the correct two angles! :-)
Answer:
The most correct option for the recursive expression of the geometric sequence is;
4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2
Step-by-step explanation:
The general form for the nth term of a geometric sequence, aₙ is given as follows;
aₙ = a₁·r⁽ⁿ⁻¹⁾
Where;
a₁ = The first term
r = The common ratio
n = The number of terms
The given geometric sequence is 7, 14, 28, 56, 112
The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2
r = 2
Let, 't₁', represent the first term of the geometric sequence
Therefore, the nth term of the geometric sequence is presented as follows;
tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾
tₙ = t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁
∴ tₙ = 2·tₙ₋₁, for n ≥ 2
Therefore, we have;
t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.
Answer:
28
Step-by-step explanation:
7 x 4 = 28
:)
