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MAXImum [283]
3 years ago
11

The Sugar Sweet Company is going to transport its sugar to market. It will cost $4500 to rent trucks, and it will cost an additi

onal $150 for each ton of sugar transported. Let C represent the total cost (in dollars), and let S represent the amount of sugar (in tons) transported. Write an equation relating C to S . Then use this equation to find the total cost to transport 12 tons of sugar.
Mathematics
1 answer:
Elza [17]3 years ago
6 0
C = 4500 + 150s

4500 is fixed, so what remains is just 150$ per ton of sugar (so 150 x s)

If we substitute 12 for s we get: 

C = 4500 + 150*12

C = 6300
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All points from which of the following patterns would be contained on the given graph?
NeX [460]

Answer:

B

Step-by-step explanation:

Slope of the line is -3. y-intercept is 3.

So, the rule for this line is y= - 3x+3.

The pattern of y-values that can fit is B.

y=0, x= 1

y=-3, x=2

y=-6, x=3

and so on.

8 0
4 years ago
What is the value of X to the nearest tenth? <br> Answer options: 0.3, 14.4, 3.4
Nookie1986 [14]

Answer: x=14.4

Step-by-step explanation:

The triangle shown in the figure attache is a right triangle. Therefore, you can calculate the missing side "x" as following:

tan\alpha=opposite/adjacent

Where:

\alpha=64\°\\opposite=x\\adjacent=7

When you solve for x and substitute the values shown above, you obtain the following result:

x=7*tan(64\°)\\x=14.35

x≈14.4

3 0
3 years ago
Read 2 more answers
Use the given data to find the 95% confidence interval estimate of the population mean μ. Assume that the population has a norma
loris [4]

Answer: For 95% Confidence Interval:

Upper Limit = 110.2

Lower Limit = 97.8

95% Confidence Interval = [97.8, 110.2]

Step-by-step explanation:

Given that,

Mean(M) = 104

Standard Deviation(SD) = 10

Sample Size(n) = 10

Formula for calculating 95% Confidence Interval are as follows:

Standard error(SE) =\frac{SD}{\sqrt{n} }

                         = \frac{10}{\sqrt{10} }

                         = 3.164

⇒ M ± Z_{0.95} × SE

= 104 ± (1.96)(3.164)

= 104 ± 6.20

∴ Upper Limit = 104 + 6.20 = 110.2

   Lower Limit = 104 - 6.20 = 97.8

So,

95% Confidence Interval = [97.8, 110.2]

6 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
Gnesinka [82]

Answer: The approximate difference in the ages of the two cars is 2 years

Step-by-step explanation:

Now, since the first car (Car A) depreciates annually at a rate of 10% and is currently worth 60% or 40% less than its original value, we can calculate the number of years it took the car to depreciate to just 60% of its original worth:

= Current value/rate of depreciation

= 60%/10%

= 6 years

So, if the car depreciates by 10% every year from the year it was worth 100% of it's original value, it will take 6 years for the car to now worth just 60%

In the same manner, if the second car (Car B) is depreciating at an annual rate of 15% and is likewise currently worth just 60% or 40% less than its original value, we can calculate the number of years it will take the car to depreciate to 60% of its original worth.

= Current worth/ rate of depreciation

= 60%/15%

= 4 years

So, if the car (Car B) is depreciating at a rate of 15% per annum, the car will depreciate to just 60% in a period of 4 years.

Therefore, if the 2 cars are currently worth just 60% of their original values (recall that it took the first car 6 years and the second car 4 years to depreciate to their current values), the approximate difference in the ages of the two cars assuming they both started depreciating immediately after the years of their respective manufacture is:

= 6 years - 4 years

= 2 years

8 0
3 years ago
A total of 366 tickets were sold for the school day they were pay they were either adults tickets or students tickets.the number
JulijaS [17]

Answer:

122

Step-by-step explanation:

366 divided by 3


6 0
3 years ago
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