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Yakvenalex [24]
3 years ago
11

I WILL MARK BRAINLIST help asap 7grade math!!!!

Mathematics
1 answer:
Ymorist [56]3 years ago
8 0
-4/5 and -1/2
Taking the LCM of the 2 fractions we get the common denominator 10

-8/10 and - 5/10

Now we can see the second fraction (-5/10) is bigger
Thus the friend is wrong
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Quadrilateral BECK is known to be a rhombus. Two of the vertices are B(3,5) and C(7,-3).
Zanzabum

Answer:

a. The slope of EK is \frac{1}{2}

b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

Step-by-step explanation:

The form of the equation of a line is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept

The rule of the slope is m = \frac{y2-y1}{x2-x1} , where

  • (x1, y1) and (x2, y2) are two points on the line
  • The rule of the mid-point is (\frac{x1+x2}{2},\frac{y1+y2}{2})

∵ BECK is a rhombus

∵ The diagonal is the line that joins two opposite vertices

∵ B and C are opposite vertices in the rhombus

∵ E and K are opposite vertices in the rhombus

∴ BC and EK are the diagonals of the rhombus BECK

∵ The diagonals of the rhombus are ⊥ and bisect each other

∴ EK is ⊥ bisector to BC

→ Let us find the slope and the mid-point of BC

∵ B = (3, 5) and C = (7, -3)

∴ x1 = 3 and y1 = 5

∴ x2 = 7 and y2 = -3

→ Substitute them in the rule of the slope above to find it

∵ m = \frac{-3-5}{7-3} = \frac{-8}{4} = -2

∴ m = -2

∴ The slope of BC = -2

→ To find the slope of EK reciprocal the slope of BC and change its sign

∴ m⊥ = \frac{1}{2}

∴ The slope of EK = \frac{1}{2}

a. The slope of EK is \frac{1}{2}

→ Substitute the value of the slope in the form of the equation above

∵ y = \frac{1}{2} x + b

→ To find b substitute x and y in the equation by the coordinates

   of a point on the line

∵ The mid-point of BC is the mid-point of EK

∵ The mid-point of BC = (\frac{3+7}{2},\frac{5+-3}{2}) = (\frac{10}{2},\frac{2}{2}) = (5, 1)

∴ The mid-point of EK = (5, 1)

→ Substitute x by 5 and y by 2 in the equation

∵ 1 =  \frac{1}{2}(5) + b

∴ 1 =  \frac{5}{2} + b

→ Subtract  \frac{5}{2} from both sides

∴  -\frac{3}{2} = b

→ Substitute the value of b in the equation

∵ y = \frac{1}{2} x + -\frac{3}{2}

∴ y = \frac{1}{2} x -  \frac{3}{2}

b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

6 0
3 years ago
F(x + h) – f(x)
olga nikolaevna [1]

9514 1404 393

Answer:

  -6x² -6xh -2h²

Step-by-step explanation:

Apparently, you want ...

  (f(x+h) -f(x))/h

for f(x) = 14 -2x³

That difference quotient is ...

  \dfrac{f(x+h)-f(x)}{h}=\dfrac{(14 -2(x+h)^3)-(14-2x^3)}{h}\\\\ =\dfrac{14-2(x^2 +3x^2h+3xh^2+h^3)-14+2x^3}{h}=\dfrac{-6x^2h-6xh^2-2h^3}{h}\\\\ =\boxed{-6x^2 -6xh-2h^2}

3 0
3 years ago
WILL MARK YOU BRAINLIEST
Nonamiya [84]

Answer:

_____________the answer is (-7,-3)______________

4 0
3 years ago
Please help I have another question with the same criteria
kondaur [170]
The answer is 7 because it’s 7
5 0
3 years ago
Read 2 more answers
What is the value of a in the polynomial
Alexandra [31]

Answer: a= 16

Step-by-step explanation:

We have the following expression:

(y-4)(y^2 +4y +16)

To find the value of the coefficient "a" you must use the distributive property to multiply the expression:

(y-4)(y^2 +4y +16)

until you transform it to the form:

y^3 +4y^2 +ay -4y^2 -ay-64

Then we have

(y-4)(y^2 +4y +16)\\\\(y^3 +4y^2 +16y -4y^2 -16y-64)\\\\

Therefore the value of a in the polynomial is 16

5 0
3 years ago
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