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3 years ago

BRAINLIEST

Mathematics

1 answer:

kotegsom [21]3 years ago

5 0

Answer: I think Plan A is the cheapest

Step-by-step explanation:

I would say this because all it is is a 10 cent incline and 30 dollars cheaper, meaning it would take almost 15 weeks to earn 30 dollars on the plan a, while plan b will already be at like 100 Dollars.

I am sorry if I didn't completely answer your question but I did the best to my ability

Thanks!

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As a puppy, Cricket weighed 3 3/4 pounds. At her 1-year check-up with the vet, Cricket weighed 12.5 pounds. How much weight did

barxatty [35]

Answer:
8.75lb :)

Explanation:
12.5 - 3 3/4 = 8.75lb

3 0

3 years ago

Read 2 more answers

I need the answer for these questions please my mom is at work and cannot help me

Bess [88]

Answer:

2 1/2 gallons

about 1 more quart

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3 years ago

A paperweight has the shape of a regular triangular Pyramid find the area of the paperweight

s2008m [1.1K]

Answer:

Step-by-step explanation:

area of a triangular pyramid = base area + 3(triangular sides area)

= 1/2 (5) 4.3 + 3 (1/2 x 5 x 8)

= 10.75 + 3(20)

= 70.75 in²

5 0

3 years ago

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

inessss [21]

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

That is,

Consider X be the length of the pregnancy

Mean and standard deviation of the length of the pregnancy.

Mean $\mu =266\\$

Standard deviation \sigma =15

For part (a) , to find the probability of a pregnancy lasting 308 days or longer:

That is, to find $P(X\geq 308)$

Using normal distribution,

$z=\frac{X-\mu}{\sigma}$

$z=\frac{308-266}{15}$

$=\frac{42}{15}$

Thus $z=2.8$

So $P\left (X\geq 308 \right )=1-P(X$

$=1-P(z$

$=1-Table\: value\: of\: 2.8$

$=1-0.99744$

$=0.00256$

Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.

This the answer for part(a): 0.00256

For part(b), to find the length that separates premature babies from those who are not premature.

Given that the length of pregnancy is in the lowest 3%.

The z-value for the lowest of 3% is -1.8808

Then $X=\frac{X-\mu}{\sigma}\Rightarrow X=z*\sigma+\mu$

This implies $X=-1.8808*15+266=237.788$

Thus the babies who are born on or before 238 days are considered to be premature.

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3 years ago

If x=4 and w=-9 then solve -8(5 - 4x) + 6w

kvasek [131]

Answer:

Step-by-step explanation:

-8(5 - 4x) + 6w

Let x= 4 and w = -9

-8( 5 - 4(4)) + 6(-9)

Parentheses first

-8 (5-16) -54

Multiply and divide

-8(-11) -54

88 -54

7 0

3 years ago