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3 years ago

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Consider a triangle ABC like the one below. Suppose that A=121° C = 25°, and a=64. (The figure is not drawn to scale.) Solve the

triangle.
Round your answers to the nearest tenth.
If there is more than one solution, use the button labeled "or".

1 answer:

agasfer [191]3 years ago

6 0

Answer:

4

Step-by-step explanation:

i need points bro

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Christine is 4 years younger than Mark. 3 years from now, she will be two-thirds as old as Mark find their present ages.Complete

icang [17]

Answer:Mark Is 9 years old; Christine is 5 years old

Step-by-step explanation:

Present age

LET mark age be x

Christine be x-4 yrs

In 3 yrs Time

Mark will be x+3 yrs old

Christine will be (x -4 +3) = x-1 years old

Also, In 3 years time

Christine = 2/3 Mark

such that

x-1 = 2/3(x+3)

x -1= 2x+6 / 3

3x -3= 2x+6

3X--2X = 6+3

=X=9

Mark Is 9 years old

Christine is x -4 = 9-4=5 years old

5 0

3 years ago

Can you help me plssssss

photoshop1234 [79]

120 square centimeters i think?

8 0

2 years ago

Read 2 more answers

betty closes the nozzle and fills it completely with a liquid. She then opens the nozzle. If the liquid drips at the rate of 14

natta225 [31]

Answer:

4.71 minutes

Step-by-step explanation:

Incomplete question [See comment for complete question]

Given

Shape: Cone

$r = 3$ -- radius

$h = 7$ --- height

$Rate = 14in^3/min$

Required

Time to pass out all liquid

First, calculate the volume of the cone.

This is calculated as:

$V = \frac{1}{3} \pi r^2h$

This gives:

$V = \frac{1}{3} * 3.14 * 3^2 * 7$

$V = \frac{1}{3} * 197.82$

$V = 65.94in^3$

To calculate the time, we make use of the following rate formula.

$Rate = \frac{Volume}{Time}$

Make Time the subject

$Time= \frac{Volume}{Rate }$

This gives:

$Time= \frac{65.94in^3}{14in^3/min}$

$Time= \frac{65.94in^3}{14in^3}min$

Cancel out the units

$Time= \frac{65.94}{14} min$

$Time= 4.71 min\\$

3 0

3 years ago

Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.

lyudmila [28]

Answer:

The area of the second enlargement is 1,944 square inches

The area of the second enlargement is (3 squared) squared times the original area.

The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

so

First enlargement

Multiply the original dimensions by a scale factor of 3

$Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches$

The area of the first enlargement is

$18(12)=216\ in^2$

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

$Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches$

The area of the second enlargement is

$54(36)=1,944\ in^2$

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

$[(3^2)]^2(24)=1,944\ in^2$

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

$3(216)=648\ in^2$

so

$648\ in^2 \neq 1,944\ in^2$

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

$\frac{216}{24}=9$

8 0

3 years ago

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4 times a number plus 16 is more than 28.

umka21 [38]

4*4= 16 + 16= 32 :) You could do 4 * 4 that equals 16 then add 16 to that to get over 28.

4 0

3 years ago

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