Answer:
There were 333 seniors in 1990
153 seniors had jobs in 2010.
Step-by-step explanation:
Let the number of high school seniors in 1990 = x
75% of x had jobs in 1990
In 2010 there were 50 more seniors. That is, the number of seniors is x+50.
40% of (x+50) had jobs in 2010.
Total number of jobs in both years = 403.
\[0.75 * x + 0.4 * (x + 50) = 403\]
\[0.75 * x + 0.4 * x + 20 = 403\]
=> \[1.15 * x = 403 - 20\]
=> \[1.15 * x = 383\]
=> \[x = 383/1.15\]
=> \[x = 333\]
Number of seniors having job in 2010 = 0.4 * (333 + 50) = 0.4 * 383 = 153.2 = 153(approx)
Answer:
You need to take a screenshot or picture of the problem then I'll help you
Step-by-step explanation:
Answer:
Step-by-step explanation:
As the equation is given in the question as follows.
2.5(6x-4)=10+4(1.5+0.5x)
open the bracket
2.5 × 6x - 2.5 × 4 = 10 + 4 × 1.5 + 4 ×0.5x
15x - 10 = 10 + 6 + 2x
15x - 2x = 16 + 10
13x = 26
x = 2
Answer:
114
Step-by-step explanation:
if,
24inches=72cents
38inches=?
we cross multiplication,
38times72=2736 divide with 24=114
The answer is114
Answer:
100%
Step-by-step explanation:
Probability of a product showing up in warehouse A =60%
Probability of a product showing up in warehouse B = 80%
Probability of 2 product showing up in warehouse A is
Probability of 1 product showing up in A and probability of 1 product showing up in A
A n A = 60% x 60% = 0.6 x 0.6 = 0.36 =36%
Probability of 2 product showing up in warehouse B is
Same as above
Probability of 1 product showing up in B and probability of 1 product showing up in B
B n B = 80% x 80% = 0.8 x 0.8 = 0.64= 64%
Probability of 2 product showing up in same warehouse is define as
Probability of 1 product showing up in A and probability of 1 product showing up in A or
Probability of 1 product showing up in B and probability of 1 product showing up in B
(AnA) U (BnB) =
36% + 64% = 0.36 + 0.64= 1
100%
