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kolezko [41]
3 years ago
13

Find the distance between the pair of points. Round your answer to the nearest tenth if necessary.

Mathematics
1 answer:
Kaylis [27]3 years ago
6 0

Answer:

The distance between the pair of points is 12.0 (to the nearest tenth)

Step-by-step explanation:

The distance between a pair of points in a coordinate system is found by the formula:

d =\sqrt({x_2-x_1)^2+(y_2-y_1)^2}

where, the points are:

(x_1,y_1)\ and\ (x_2,y_2)

From the graph,

(x_1,y_1)=(-6,-2)\\(x_2,y_2)=(2,7)

Substitute the points into the formula:

d=\sqrt{(2-(-6)^2+(7-(-2)^2} \\d=\sqrt{(2+6)^2+(7+2)^2} \\d=\sqrt{8^2+9^2} \\d=\sqrt{64+81} \\d=\sqrt{145} \\\d=12.0

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Find the volume of the composite figure to the nearest tenth. Use 3.14 for pi.
Vilka [71]

Given:

In the given fig,

The radius of the cylinder = 15 ft

The height of the cylinder = 26 ft

The height of the cone = 21 ft

The radius of the cone = 15 ft

To find the volume of the cone, the volume of the cylinder and the composite figure.

Formula

The volume of the given composite fig is

V = V_{1} +V_{2}

where, V_{1} be the volume of the cone.

V_{2} be the volume of the cylinder.

V_{1} = \frac{1}{3} \pi r^{2} h, r be the radius and h be the height.

V_{2} = \pi r^{2} h, r be the radius and h be the height.

Now,

Putting, r = 15, h = 21 and π = 3.14 we get,

V_{1} = \frac{1}{3} (3.14)(15^{2} )(21) cube ft

V_{1} = 4945.5 cube ft

Again,

Putting,

V_{2} = (3.14)(15^{2} )(26) cube ft

V_{2} = 18369 cube ft

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Hence,

a) The volume of the cone is 4945.5 cube ft.

b) The volume of the cylinder is 18369 cube ft.

c) The volume of the composite figure is 23314.5 cube ft.

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