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Nadya [2.5K]
2 years ago
6

Crackers were on sale 2 for 5.50. I bought three packs, How much did I spend?

Mathematics
3 answers:
MrRissso [65]2 years ago
8 0

Answer:

6.75

Step-by-step explanation:

2 crackers=5.50

1 cracker=5.50÷2

=2.25

3 crackers=2.25×3

=6.75

pochemuha2 years ago
8 0

Answer:

QUESTION

Crackers were on sale 2 for 5.50. I bought three packs, How much did I spend?

=========================================

ANSWER

6.75

=========================================

#CarryOnLearning

(◍•ᴗ•◍)✧*。

tensa zangetsu [6.8K]2 years ago
6 0

Answer:

QUESTION

Crackers were on sale 2 for 5.50. I bought three packs, How much did I spend?

=========================================

ANSWER

6.75

=========================================

#CarryOnLearning

(◍•ᴗ•◍)✧*。

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Answer:

Area = 240

Step-by-step explanation:

The roof is 4 Isosceles triangles as two sides are the same and the base is different.  The equation for area of an isosceles triangle is area = (1/2) · b · h.  

      Starting the equation, we know the height = 10 based on the graphic, but we need solve for the base using the information provided in the problem 25.  

      If the square gazebo is 48 ft around, then perimeter = 48.  To find one side of the "SQUARE" gazebo, divide the perimeter by 4 to find one side having a length/base of 12.  

      We can assume that the base of the gazebo is the same length as the base of the roof, so the base is 12 as well.  

Finishing the formula we have:

Area of 1 side of gazebo roof= (1/2) * b * h = (1/2) * 12 * 10 = 60  

There are 4 sides to the roof, so multiply the Area of the one side by 4 to find the final result.

Area of full Gazebo roof = 60 * 4 = 240

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vesna_86 [32]

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Step-by-step explanation:

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2 years ago
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AlexFokin [52]

Answer:

\large\boxed{PS=10\sqrt5}

Step-by-step explanation:

ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:

\dfrac{QR}{RP}=\dfrac{RP}{RS}

We have:

QR=5,\ RS=20

Substitute:

\dfrac{5}{RP}=\dfrc{RP}{20}                <em>cross multiply</em>

RP^2=(5)(20)\\\\RP^2=100\to RP=\sqrt{100}\\\\RP=10

Use the Pythagorean theorem:

PS^2=PR^2+RS^2

Substitute:

PS^2=10^2+20^2\\\\PS^2=100+400\\\\PS^2=500\to PS=\sqrt{500}\\\\PS=\sqrt{100\cdot5}\\\\PS=\sqrt{100}\cdot\sqrt5\\\\PS=10\sqrt5

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