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12345 [234]
3 years ago
14

Find the perimeter of rectangle A

Mathematics
2 answers:
Arlecino [84]3 years ago
5 0

Answer:

The perimeter of rectangle A is 8x+6y or 2(4x+3y)

Step-by-step explanation:

The perimeter of a figure is the sum of its boundary dimensions.

The perimeter of rectangle A is:

4x+4x+3y+3y=8x+6y

Factorizing,

8x+6y=2(4x+3y)

tatyana61 [14]3 years ago
5 0
Kdndjdidhdjdhdjdndjbdbdbdhdbdv
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The Walt Disney Company paid a $0.35 annual dividend on a day it closed at a price of
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Step-by-step explanation:

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Sholpan [36]

There are 12 squares in each 4 x 3 grid.

25% of 12 = 3

This means that there should be 3 shaded squares in the grid.

Your answer is B. because it has 3 shaded squares.

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Answer:

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3 years ago
The Wonderful Widget Company's earnings have declined to the point where they need to reduce the number of employees from 1500 1
AleksandrR [38]

Answer:6%

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3 years ago
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

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