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3 years ago

PLZ HELP !!!!!!!!!!!! Square roots

Mathematics

1 answer:

Vilka [71]3 years ago

8 0

Answer:

Step-by-step explanation:

$\sqrt{50} \ is \ between \ \sqrt{49} \ and \ \sqrt{64}.$

50 is little away from 49 and 50 is far away from 64.

$\sqrt{49} = \sqrt{7*7}=7 \ and \ \sqrt{64}=8$

As 50 is closer to 49 the square root of 50 will be closer to 7 than 8 and so it should be just a little over 7

√50 ≈ 7.1

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A line passing (a,3) and (5,5) is perpendicular to a line passing through (0,0) and (1,a) Find the value of a.

vodka [1.7K]

Answer:

a = -5

Step-by-step explanation:

(5 - 3)/(5 - a)

2/(5 - a)

perpendicular of 2/(5 - a) = -(5 - a)/2

(a - 0)/(1 - 0) = -(5 - a)/2

a/1 = -(5 - a)/2

2a = -5 + a

a = -5

6 0

4 years ago

(2)/(3) =( 4)/( 3+x) help give brainliest if correct and explanation please

Juli2301 [7.4K]

Answer:

(2)/(3) =( 4)/( 3+x)

Cross multiply

2*(3+x)= 4*3

Solve bracket

6+2x=12

Subtract 6 from both sides

2x=6

Divide both sides by 2

x=3

Hope it helps :-)

7 0

3 years ago

Read 2 more answers

Re-write the quadratic function below in Standard Form<br> y=-3 (x - 2)² – 7

pav-90 [236]

Answer:

$y=-3x^2+12x-19$

Step-by-step explanation:

we know that

The quadratic equation in standard form is equal to

$y=ax^{2} +bx+c$

we have

$y=-3(x-2)^{2}-7$

This is a quadratic equation in vertex form

Convert to standard form

$y=-3(x^2-4x+4)-7$

Apply distributive property

$y=-3x^2+12x-12-7$

Combine like terms

$y=-3x^2+12x-19$ ----> quadratic equation in standard form

3 0

3 years ago

All you need is in the photo I DON'T WANT STEP BY STEP ANSWER FAST please fdsd

Brut [27]

We have the following:

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ a=5 \\ b=0 \\ c=-80 \end{gathered}$

replacing:

$\begin{gathered} x=\frac{-0\pm\sqrt[]{0^2-4\cdot5\cdot-80}}{2\cdot5}=\frac{\pm\sqrt[]{1600}}{10}=\frac{\pm40}{10}=\pm4 \\ x_1=4 \\ x_2=-4 \end{gathered}$

6 0

1 year ago

Need help with this math problem

Andre45 [30]

Hey There!

First you would need to factor out the two.

-4x^3/2 = -2x^3

2x^2/2= x^2

12x/2= 6x

6/2= 3

Now we have.

-2x^3+x^2+6x+3 / x+1

We would then factor with polynomial division, and then we should have.

-2(2x^2 - 3x - 3)(x+1) / x+1

We would then cancel out the x+1

Therefore, the answer would be $\boxed{-2(2x^2-3x-3)}$

Hope this helped!

8 0

4 years ago

PLZ HELP !!!!!!!!!!!! Square roots ​

PLZ HELP !!!!!!!!!!!! Square roots