4x-2y = 4
= -2y = 4-4x
= y = (4x + 4)/ 2
y = 2x - 2
h(x) = 2x-2
To find y-intercept, find h(0)
= 2(0) - 2 => -2
Y-intercept = (0,-2)
Answer:
distance = 50 - (-150) = 50+150 = 200
Therefore, the distance between -150 and 50 is 200 units.
Please check the attached diagram below.
Step-by-step explanation:
Given the numbers
The number 50 is plotted 50 units to the right from position 0 on the number line, which is shown on the number line on the attached diagram below.
The number -150 is plotted 150 units to the left from position 0 on the number line, which is shown on the number line on the attached diagram below.
The distance between 50 and -150 can be calculated by subtracting -150 from 50.
i.e.
distance = 50 - (-150) = 50+150 = 200
Therefore, the distance between -150 and 50 is 200 units.
Please check the attached diagram below.
The answer your looking for is B
Answer:
Step-by-step explanation:
Question (3)
The given expression is,
![\frac{4(x-3)}{3}=20](https://tex.z-dn.net/?f=%5Cfrac%7B4%28x-3%29%7D%7B3%7D%3D20)
Statements Proof
1).
1). Given
2).
2). Multiplication property of equality
3). 4x - 12 = 60 3). Distributive property
4). 4x = 72 4). Addition property of equality
5). x = 18 5). Division property of equality
Question (4)
Equations are,
5x + 10 = 30 ------(1)
5(x + 10) = 30 ------(2)
From equation (1),
5x + 10 = 30
5x = 30 - 10
x = 4
From equation (2),
5(x + 10) = 30
(x + 10) = 6
x = 6 - 10
x = -4
Therefore, solutions of both the equations are different.
Answer:
3.200×107 h
Step-by-step explanation: