Question

What is the equation of the line, in slope-intercept form, that passes through (3,-1) and (-1, 5)?

Answer 1

Answer:

$2y = -3x+7$

Step-by-step explanation:

The coordinates are (3,-1) and (-1,5)

Finding the slope :

Slope = $\frac{rise}{run}$

Slope = $\frac{5+1}{-1-3}$

Slope = $\frac{6}{-4}$

Slope = $-\frac{3}{2}$

Now Finding y-intercept.

For this, we'll take any point

Let it be (3,-1)

So,

Point = (x,y) = (3,-1)

=> x = 3, y = -1

Putting in slope intercept form to get b

=> $y = mx+b$

=> -1 = (3)($-\frac{3}{2}$) + b

=> b =  -1 +  $\frac{9}{2}$

=> b = $\frac{7}{2}$

Putting m and b in the slope intercept form to get the required equation of line

=> $y = mx+b$

=> $y = \frac{-3x+7}{2}$

=> $2y = -3x+7$