Find 2 numbers with a sum of 65. Twice the lesser number is 10 more than the greater number.

2 answers:

8 0

Answer:

25 & 40

Explanation:

$x+y=65\\2x-10=y\\\\x=65-y\\130-2y-10=y\\120-2y=y\\120=3y\\y=40\\\\x+y=65\\x+40=65\\x=25$

7 0

25 and 40
Bdbsjjd snella a nananana
Skid s

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