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3 years ago

7

[297÷3 + { 4 × 3 ( 20 – 36 ÷ 5 – 2)}]

1 answer:

maw [93]3 years ago

4 0

Here is the answer to your problem:

<h3><u>https://brainly.in/question/10886862</u></h3>

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What is the range of the function y=2e^x-1

STatiana [176]

The range is (-1,∞),{yly>-1}

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3 years ago

A bakery is offering a promotion where a customer can buy a dozen cookies for $10.00. Normally, the cookies cost $1.15 each. By

jenyasd209 [6]

Answer:

28%

Step-by-step explanation:

The result is about 27.5362% so if we round it it will be 28%

5 0

3 years ago

Read 2 more answers

1. How much more is of is of a gallon of water 3/8 than of a gallon of water ? 1/4

masya89 [10]

Answer: 3/8 * 4 = 12/8 = 1 4/8 = 1 1/2

your answer is 1 1/2

Step-by-step explanation:

8 0

2 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

4 0

4 years ago

Y is a directly proportional to x and y= 15 when x =6. Find x when y =40.

Dahasolnce [82]

Answer:

x = 16 when y = 40

Step-by-step explanation:

as y is directly proportional to x:

y = x

y = k x .........k is here constant.

15 = k * 6

k = 15/6

k = 5/2

Here constant, k is (5/2)

So when y = 40

y = k x

40 = (5/2)x

x = 40(2/5)

x = 16

7 0

2 years ago