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Vika [28.1K]
3 years ago
8

How much net force is required to accelerate a 10 kg mass at 1.5 m/s2?

Physics
1 answer:
Valentin [98]3 years ago
8 0

Answer:

F = 15N

Explanation:

The explanation is on the above photo.

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What force must be provided to accelerate a 64-lb object upward at a rate of 2 ft/s2? (Use g = 32 ft/s2.)
vovikov84 [41]

Answer:

The force that must be provided to accelerate the object = 302.196 N

Explanation:

<em>Force</em>: Force can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N).

Ft - W = ma............ Equation 1

Ft = W + ma .......... Equation 2

Where Ft = force provided, W = weight of the object, m= mass of the object, a = acceleration of the object.

<em>Given: mass = 64 lb, g = 32 ft/s² a = 2 ft/s²</em>

<em>Conversion: (i)  from 64 pounds to Kg = 64/2.2046</em>

<em>                       = 29.03 kg</em>

<em>   (ii)  from 2 ft/s² to m/s² = 0.3048 × 2 = 0.6098 m/s²</em>

<em> (iii) from 32 ft/s² to m/s² = 0.3048×32 = 9.8 m/s².</em>

and W = mg = 29.03 × 9.8 = 284.494 N,

Substituting these values into equation 2,

Ft = 284.494 + 29.03×0.6098

Ft = 284.494 + 17.7

Ft = 302.196 N

Therefore, the force that must be provided to accelerate the object = 302.196 N

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4 years ago
What distance does the car cover in the first 4.0 seconds of its motion?
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The distance covered is (4) times (the car's average speed during that time).
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Prior to the Panama Canal, __________ was a major route between the Atlantic and Pacific oceans.
Bingel [31]
The Rio Grande was the major route prior to the Panama Canal.
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4 years ago
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How does the orbital velocity of the earth compare to the of mercury?
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After my ythorough researching, the orbital velocity of the Earth compare to the Mercury is relative to each other. In addition, Mercury orbits the Sun and it is within the Earth's orbit as its lesser or inferior. The correct answer to the following given statement above is relative to each other.

 

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3 years ago
An astronaut landed on a far away planet that has a sea of water. To determine the gravitational acceleration on the planet's su
ra1l [238]

Answer:

Acceleration due to gravity will be g=17.3m/sec^2

Explanation:

We have given gauge pressure P = 3.8 atm = 3.8×101325 = 385035 Pa

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Density \rho =1000kg/m^3

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We know that pressure is given by

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So 385035=1000\times g\times 24.3

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