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Llana [10]
3 years ago
11

Help me, please this isn't really so hard, but I really need help

Mathematics
1 answer:
Oxana [17]3 years ago
3 0

Answer:

what topic???????????????????

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Quadrilateral ABCD is plotted with coordinates A(3,7), B(6,1), C(-6,-8) and D(-5,1). Using coordinate geometry, prove that ABCD
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Answer:

Step-by-step explanation:

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in the next several games , the pitcher threw a total of 384 pitches and used a fastball 240 times. What decimal should juanita
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Divide the number of fast balls by the total number of pitches:

240 / 384 = 0.625

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Read 2 more answers
What is the measure of WUX in Circle V ?
Alja [10]

Answer:

arc\ WUX=120^o

Step-by-step explanation:

<u><em>The complete question is:</em></u>

In circle V, angle WXZ measures 30°. Line segments WV, XV, ZV, and YV are radii of circle V. Circle V is shown. Line segments W V, X V, Z V, and Y V are radii. Lines are drawn from point W to point X and from point Z to point Y to form secants. Point U is on the circle between points W and X. What is the measure of Arc W U X in circle V?

The picture of the question in the attached figure

step 1

Find the measure of angle XWV

we know that

The triangle VWX is an isosceles triangle, because has two equal sides (VX=VW)

we have

m\angle WXZ=30^o\\m\angle WXV=m\angle WXZ

so

m\angle WXV=30^o

Remember that an isosceles triangle has two equal interior angles

so

step 2

Find the measure of angle WVX

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

m\angle\ WVX+m\angle XWV+m\angle WXV=180^o

substitute the given values

m\angle WVX+30^o+30^o=180^o\\m\angle WVX=180^o-60^o=120^o

step 3

Find the measure of arc WUX

we know that

arc\ WUX=m\angle WVX ----> by central angle

we have

m\angle WVX=120^o

therefore

arc\ WUX=120^o

4 0
4 years ago
PLEASE HELP FIRST CORRECT ANSWER GETS BRAINLIEST AND LOTS OF POINTS
kykrilka [37]

Answer: y= -4

Step-by-step explanation:

7 0
3 years ago
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