Question

I need help with this question plzzz

Answer 1

Step-by-step explanation:

a refuse regular function tries to calculate a y value for a given x (input) value.

the inverse function turns this around and tries to calculate the x (input) value for a given y functional value.

e.g. when we know f(x) = 8, then what was the x value leading to this 8 fungible value ?

in order to turn this around, we solve the same functional equation for x instead of for y.

in our example here

f(x) = y = 3x -6

y + 6 = 3x

x = y/3 + 2

and now, to write the inverse function as normal function, we simply exchange the x and y names :

y = x/3 + 2