<img src="https://tex.z-dn.net/?f=f%28x%29%3D%28x%2B4%29%5E2%5C%5C" id="TexFormula1" title="f(x)=(x+4)^2\\" alt="f(x)=(x+4)^2\\"

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Thepotemich [5.8K]

2 years ago

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Mathematics

1 answer:

Yuri [45]2 years ago

3 0

Answer:

x²+8x+16

Step-by-step explanation:

f(x) = (x+4)²

= (x+4)(x+4)

= x² + 4x + 4x + 16

= x² + 8x + 16

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The exponential function f(x) = 3(5)x grows by a factor of 25 between x = 1 and x = 3. What factor does it grow by between x = 5

Delvig [45]

Answer:

B) 25

Step-by-step explanation:

Given exponential function:

$f(x)=3(5)^x$

The growth factor between $x=1$ and $x=3$ is 25.

To find the growth factor between $x=5$ and $x=7$

Solution:

The growth factor of an exponential function in the interval $x=a$ and $x=b$ is given by :

$G=\frac{f(b)}{f(a)}$

We can check this by plugging in the given points.

The growth factor between $x=1$ and $x=3$ would be calculated as:

$G=\frac{f(3)}{f(1)}$

$f(3)=3(5)^3$

$f(1)=3(5)^1$

Plugging in values.

$G=\frac{3(5)^3}{3(5)^1}$

$G=\frac{(5)^3}{(5)^1}$ (On canceling the common terms)

$G=(5)^{(3-1)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Similarly the growth factor between $x=5$ and $x=7$ would be:

$G=\frac{f(7)}{f(5)}$

$f(7)=3(5)^7$

$f(5)=3(5)^5$

Plugging in values.

$G=\frac{3(5)^7}{3(5)^5}$

$G=\frac{(5)^7}{(5)^5}$ (On canceling the common terms)

$G=(5)^{(7-5)}$ (Using quotient property of exponents $\frac{a^b}{a^c}=a^{(b-c)}$ )

$G=(5)^{2}$

∴ $G=25$

Thus, the growth factor remains the same which is =25.

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Vilka [71]

Answer:

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Step-by-step explanation:

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Elan Coil [88]

Answer:

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

P represents the principal or initial amount invested or collected as a loan.

R represents interest rate.

T represents the duration of time in years before the loan is bald back.

From the information given,

P = 1290

I = 5.75

Since there are 365 days in a year,

t = 65/365 = 0.1781 years

Therefore,

5.75 = (1290 × r × 0.1781)/100

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r = 5.75/2.29749

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