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DedPeter [7]
3 years ago
9

The _______________ layer of the TCP/IP protocol suite is responsible for making sure that what leaves one end of the network ar

rives at the other end of the network exactly the same.​
Computers and Technology
1 answer:
seropon [69]3 years ago
7 0

Answer:

Transport layer

Explanation:

The transport layer is responsible for maintaining end to end communication between devices connected on a network.

The TCP/IP determines how data is exchanged between devices connected on a network by providing end to end communications that determines how it should be broken into packets.

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A level breach of security could be expected to have a severe or catastrophic adverse effect on organizational operations, organ
rewona [7]

Answer:

Option D is correct.

Explanation:

A high-level safety violation could be anticipated to have a serious or disastrous negative impact on organisational activities, organisational assets.

The effect of the violation on an organisation may be staggering, and sometimes unknown until the outcomes are achieved. It is strange that, owing to harmful or neglectful acts, the greatest incidents of compromise come from within the business ; it requires time for an organisation to recover.

8 0
3 years ago
What are the five types of pointing devices?
choli [55]

Answer:

mouse, track ball, stick, touch pad, tablet

6 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
1. A green traffic sign means
NeX [460]

Answer:

general regulatory and speed control.

7 0
3 years ago
______ is data that is entered into a computer. ______ is the result produced by a computer.
Umnica [9.8K]
Input
Output
(Sorry for not being detailed)
5 0
3 years ago
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