Answer:
The probability of hitting a single or a double is 1/5 or 20% or 20/100 or 0.2
Step-by-step explanation:
In probability, whenever we are to answer an ‘or’ question, we add up the probabilities involved.
The probability of hitting a single is 15%, that is same as 15/100 or just simply 0.15
The probability of hitting a double is 5%, that is simply 5/100 or just simply 0.05
The probability of hitting a single or a double = Probability of hitting a single + Probability of hitting a double = 0.15 + 0.05 = 0.20 or 20/100 or 1/5
In this question, the Poisson distribution is used.
Poisson distribution:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Parameter of 5.2 per square yard:
This means that
, in which r is the radius.
How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?
We want:

Thus:

We have that:


Then





Thus, the radius should be of at least 0.89.
Another example of a Poisson distribution is found at brainly.com/question/24098004
3*4 + 1*5 / 5*4=
12+5/20=
17/20
The answer is definitely 7xf
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The probability of passing the test is 
The sample size is n = 10
Generally the distribution of the comprehensive testing of equipment follows a binomial distribution
i.e

and the probability distribution function for binomial distribution is

Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as

=> ![P(X \ge 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}] + [^{10}C_{10} * (0.95)^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%20%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%280.95%29%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \ge 9) = [0.3151] + [0.5987]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B0.3151%5D%20%2B%20%5B0.5987%5D%20)
=> 