All categories

3 years ago

12. What is the solution to the equation below* 9 points 5(x – 7) = 20 Your answer

Mathematics

1 answer:

yarga [219]3 years ago

6 0

Answer:

X=11

Step-by-step explanation:

11-7=4 5(4)=20 So X equals 11

You might be interested in

Where do parabolas store their holiday decorations?

Naya [18.7K]

Answer:

where...................

Step-by-step explanation:

.........................

6 0

3 years ago

The probability that a newborn baby at a certain hospital is male is 50%. Find the probability that 7 or 8 out of 10 babies born

marin [14]

Answer:

0.1611

Step-by-step explanation:

Uaing the binomial probability relation :

p = 0.5 ; q = 1 - p = 0.5

n = 10

Using the relation :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 7) = 10C7 * 0.5^7 * 0.5^3

P(x = 7) = 0.1172

x = 8 ;

P(x = 8) = 10C7 * 0.5^7 * 0.5^3

P(x =8) = 0.0439

P(x = 7 or x = 8) = 0.1172 + 0.0439 = 0.1611

4 0

3 years ago

Factor this trinomial completely.<br> 2x^2 + 10x + 8

Nikitich [7]

2x^2 + 10x + 8
=2( x + 1) (x + 4)

7 0

3 years ago

Read 2 more answers

Really need help Pls

Studentka2010 [4]

Answer:

20.57 cm

Step-by-step explanation:

Circumference of half circle = diameter + half of circumference

$= 8 +\dfrac{2\pi r}{2}\\\\\\= 8 + \pi r\\\\= 8 + 3.142 * 4\\\\= 8 + 12.568\\\\= 20.568\\\\= 20.57 \ cm$

6 0

2 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

3 years ago