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Ahat [919]
3 years ago
7

A grocery store gives a 10$ gift card for every 25th customer and 20$ gift card for every 60th customer. Which customer will rec

eive both gift cards
Mathematics
2 answers:
swat323 years ago
6 0

Answer:

Number 300 client

Step-by-step explanation:

MCM of 25 and 60 is 300

AlladinOne [14]3 years ago
5 0

Answer:

The 300th customer.

Step-by-step explanation:

The one who  is the Lowest Common Multiple of 25 and 60.

25 = 5*5.

60 = 2*2*3*5

So the LCM is 2*2*3*5*5 = 300.

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Scientists use the system of
AveGali [126]

Answer:

scientific notation is the system to write very large or very small number.

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3 years ago
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Let AB be the directed line segment beginning at point A(5 , 5) and ending at point B(19 , 16). Find the point P on the line seg
Ede4ka [16]

Answer:

(9, 57/7)

Step-by-step explanation:

Given the coordinates A(5 , 5)  and B(19 , 16), divided by the point P in the ratio 5:2, to get the coordinate of P, we will use the formula;

P(X, Y) = {{ax1+bx2/a+b, ay1+by2/a+b}

X = ax1+bx2/a+b

Substitute the given values

X = 5(5)+2(19)/5+2

X = 25+38/7

X = 63/7

X = 9

Similarly;

Y = 5(5)+2(16)/5+2

Y = 25+32/7

Y = 57/7

Hence the coordinate of point P is (9, 57/7)

7 0
3 years ago
Write an equation to represent the image. The tape diagram represents an equation. Write an equation to solve 11. 5. b​
azamat

Answer:

fvgdnsigdv356b cdhfn .44. jcbyd6.5.4.3.3.2.2.3.4.5.6.6.7.7

Step-by-step explanation:

4 0
3 years ago
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978 cubic feet into cubic meters​
nekit [7.7K]

Answer:

27.69 cubic meters​

Step-by-step explanation:

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5 0
3 years ago
Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

3 0
3 years ago
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