Answer:
Kindly check explanation
Step-by-step explanation:
To test for Difference in mean times
Null hypothesis, H0 will be, there is no difference in mean times ; m1 = m2
Alternative hypothesis, there is difference in mean times ; m1 ≠ m2
Decision region :
When p value < α ; reject the Null
Here. ;
Pvalue = 2% = 0.02
α = 1% = 0.01
Pvalue > α
0.02 > 0.01
Since, Pvalue > α ; we do not reject the Null ;
Hence, conclusion should be, there is no difference in mean times of bus and car
These two have different denominators, so you find the least common multiple. This problem goes to be 2/8+5/8, which equals 7/8。
Type o ( ii) = 6 . 25
Type A ( l^A l ^A or l ^A i ) = 18 . 75
Type B ( l ^b l^b or l ^ bi ) = 18.75
Type AB ( l ^ A l^ B) = 56.25
When a set of objects are chosen from a larger set in which the order of the object doesn't matter, we call this combination. Otherwise if the order of selection would matter this would be called a permutation.
Probability is the likelihood of selecting a particular specified object in from a specified group of objects.
Therefore our answer is B.
Tuesday:
30.80 + 1.20 = 32.00
Falling by 6.25% means it ends up being 93.75% of what it used to be (100% - 6.25% = 93.75%)
Wednesday:
32.00 * 0.9375 = 30
Thursday:
30 * 0.96 = 28.8
Friday:
28.8 * 1.025 = 29.52
Net change means you subtract to get the difference.
Net change = Final - initial
= 29.52 - 30.80
= -1.28
The stock fell $1.28
