Question

What is an equation of the line that passes through the points (-6, -4) and (3, 8)

Answer 1

Answer:

y = $\frac{4}{3}$ x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 6, - 4) and (x₂, y₂ ) = (3, 8)

m = $\frac{8-(-4)}{3-(-6)}$ = $\frac{8+4}{3+6}$ = $\frac{12}{9}$ = $\frac{4}{3}$ , then

y = $\frac{4}{3}$ x + c ← is the partial equation

To find substitute either of the 2 points into the partial equation

Using (3, 8 ) , then

8 = 4 + c ⇒ c = 8 - 4 = 4

y = $\frac{4}{3}$ x + 4 ← equation of line